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jokop
Asked:2020-07-24 16:03:17 +0000 UTC2020-07-24 16:03:17 +0000 UTC

字符串中的连续字数

  • 772

任务：如果字符串中有三个连续的单词，则打印 True，否则打印 False。该行包含数字和单词。如果单词之间有数字，我的代码将无法正常工作。添加条件result != []并没有解决问题，我没有想法。

import re
def checkio(words: str) -> bool:
    str_ = words.split()
    sum_ = 0
    for i in str_:
        result = re.findall(r'[\w*\']+', i)
        if len(result)!=0 and result != []:
            sum_ = sum_+ 1
    if sum_ >= 3:
        return True
    else:
        return False    


#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    print('Example:')
    print(checkio("Hello World hello"))

    assert checkio("Hello World hello") == True, "Hello"
    assert checkio("He is 123 man") == False, "123 man"
    assert checkio("1 2 3 4") == False, "Digits"
    assert checkio("bla bla bla bla") == True, "Bla Bla"
    assert checkio("Hi") == False, "Hi"
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

在此先感谢您的帮助。

python

4 个回答

  1. 逻辑：

    for i in str_:
        если слово:  #        if not i.isdigit():  или регуляркой
            sum_ = sum_+ 1
            if sum_ >= 3:
                return True
        else:
            sum_ = 0    
return False
    • 1

  2. 一定要定期吗？您也可以这样做，例如：

    import itertools as it

def checkit(a: str):
    if len(list(it.takewhile(lambda x: not x.isnumeric(), a.split())))>2:
        return True
    else:
        return False

checkit('hello1 1 world hello 2') #False
checkit('hello1 world hello 2') #True
    • 1
  3. Best Answer

    正则表达式解决方案：

    import re


def checkio(words: str) -> bool:
    return bool(re.match(r'.*[a-zA-Z]+\s+[a-zA-Z]+\s+[a-zA-Z]+.*', words))

    测试：

    print(checkio('13 holy hand grenade'))    # True
print(checkio('holy grenade'))            # False
print(checkio('13 666 777'))              # False
print(checkio(' eggs  eggs  eggs '))      # True
print(checkio('spam 13 spam spam'))       # False
print(checkio('eggs 13 eggs eggs eggs'))  # True
print(checkio('spam13 eg_gs eggs'))       # False
    • 1

  4. 使用正则表达式（选择三个可以包含数字但不能是数字的连续单词）：

    import re
def checkio(words: str) -> bool:
    return bool(re.findall(r'(?:\b(?:\d+[^\d\s]\w*|[^\s\d]\w+)\b\s*){3}', words))

#These "asserts" using only for self-checking and not necessary for auto-testing
if __name__ == '__main__':
    print('Example:')
    assert checkio("Hello World hello") == True, "Hello"
    assert checkio("He is 123 man") == False, "123 man"
    assert checkio("1 2 3 4") == False, "Digits"
    assert checkio("bla bla bla bla") == True, "Bla Bla"
    assert checkio("Hi") == False, "Hi"
    assert checkio("13 holy hand grenade") == True, "grenade1"
    assert checkio("holy grenade") == False, "grenade2"
    assert checkio("13 666 777") == False, "Digits"
    assert checkio(" eggs  eggs  eggs ") == True, "eggs1"
    assert checkio("spam 13 spam spam") == False, "spam"
    assert checkio("eggs 13 eggs eggs eggs") == True, "eggs2"
    assert checkio("spam13 eg_gs eggs") == True, "eggs3"
    print("Coding complete? Click 'Check' to review your tests and earn cool rewards!")

    更新：

    1. 模式，以支持包含数字的单词。
    2. 替换re.match()->re.findall()
    • 1

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