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Asked:2020-10-18 03:08:30 +0800 CST2020-10-18 03:08:30 +0800 CST

Kotlin 代码优化

  • 772
override fun <T : ViewModel> create(modelClass: Class<T>): T = when {
    modelClass.isAssignableFrom(M1ViewModel::class.java) -> M1ViewModel(dataManager, schedulerProvider)
    modelClass.isAssignableFrom(C1ViewModel::class.java) -> C1ViewModel(dataManager, schedulerProvider)
    modelClass.isAssignableFrom(C2ViewModel::class.java) -> C2ViewModel(dataManager, schedulerProvider)
    else -> throw IllegalArgumentException("Unknown ViewModel class: " + modelClass.name)
} as T

这是代码

怎样才能把代码最小化，这样就不用每次都写了

modelClass.isAssignableFrom(C2ViewModel::class.java) -> C2ViewModel(dataManager, schedulerProvider)
kotlin

1 个回答

  1. Best Answer
        if(modelClass.superclass == BaseViewModel::class.java) {
        val cArg = arrayOfNulls<Class<*>>(2)
        cArg[0] = DataManager::class.java
        cArg[1] = SchedulerProvider::class.java

        val cls = modelClass.getDeclaredConstructor(*cArg).newInstance(dataManager, schedulerProvider)
        return cls
    }else{
        throw IllegalArgumentException("Unknown ViewModel class: " + modelClass.name)
    }

    我能够像这样实现它。

    PS不是签名者，只是切换到java和kotlin

    • 0

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