主页 / 问题 / 1045535
Accepted
fermeg
Asked:2020-11-13 16:23:13 +0000 UTC2020-11-13 16:23:13 +0000 UTC

解析json数组

  • 772

有json：

[{"product_id":"1779","name":"\u0421\u0435\u0442\u0435\u0432\u043e\u0435 \u0437\u0430\u0440\u044f\u0434\u043d\u043e\u0435 \u0443\u0441\u0442\u0440\u043e\u0439\u0441\u0442\u0432\u043e AR-003 \u043a\u0443\u0431\u0438\u043a \u0431\u0435\u043b\u044b\u0439","model":"008333440","option":[],"quantity":"1","price":"290 \u0440.","total":"290 \u0440.","href":"url"},{"product_id":"1809","name":"\u041a\u0430\u0431\u0435\u043b\u044c \u0434\u043b\u044f iPhone 5\/6 Remax LESU RC-050i 1m \u0427\u0435\u0440\u043d\u044b\u0439","model":"\u0423\u0422-00000864","option":[],"quantity":"1","price":"490 \u0440.","total":"490 \u0440.","href":"url"}]

我解码这个json

$json ='[{"product_id":"1779","name":"\u0421\u0435\u0442\u0435\u0432\u043e\u0435 \u0437\u0430\u0440\u044f\u0434\u043d\u043e\u0435 \u0443\u0441\u0442\u0440\u043e\u0439\u0441\u0442\u0432\u043e AR-003 \u043a\u0443\u0431\u0438\u043a \u0431\u0435\u043b\u044b\u0439","model":"008333440","option":[],"quantity":"1","price":"290 \u0440.","total":"290 \u0440.","href":"url"},{"product_id":"1809","name":"\u041a\u0430\u0431\u0435\u043b\u044c \u0434\u043b\u044f iPhone 5\/6 Remax LESU RC-050i 1m \u0427\u0435\u0440\u043d\u044b\u0439","model":"\u0423\u0422-00000864","option":[],"quantity":"1","price":"490 \u0440.","total":"490 \u0440.","href":"url"}]';
$json = substr($json, 1, -1);
$obj = json_decode($json);

$json = substr($json, 1, -1);
$obj = json_decode($json);
print $obj->{'name'}; // 12345

但是我在数组中有两个，我怎样才能把它分开，例如，产品是 1779、1809？

php

1 个回答

  1. Best Answer

    你有一个很好的json，不需要破坏它

    // $json = substr($json, 1, -1);
$obj = json_decode($json);

    获取两个对象的数组：$obj[0]第一个产品，$obj[1]第二个

    如果要使用数组，请添加第二个参数$obj = json_decode($json, True);

    • 1

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