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Пельмень
Asked:2020-12-09 11:22:56 +0000 UTC2020-12-09 11:22:56 +0000 UTC

更换邻居

  • 772

给定一个带有数字的列表，有必要在某些地方交换相邻元素，即 A[0]与A[1],A[2]与A[3]等 打印结果列表。如果列表包含奇数个元素，则保留最后一个元素。

显示错误IndexError

a = [int(i) for i in input().split()]
for i in range(len(a)):
    if i % 2 == 0:
        a[i], a[i + 1] = a[i + 1], a[i]
print(" ".join([str(i) for i in a]))
python

2 个回答

  1. 在我看来，一个更简单的解决方案是：

    a = [int(i) for i in input().split()]
for i in range(0, len(a)-1, 2):
    a[i], a[i+1] = a[i+1], a[i]
print(" ".join([str(i) for i in a]))
    • 1
  2. Best Answer
    a = [int(i) for i in input().split()]
for i in range(len(a)-1):
    if i % 2 == 0:
        a[i], a[i + 1] = a[i + 1], a[i]
print(" ".join([str(i) for i in a]))
    • 0

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