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Эдуард Ван
Asked:2020-03-07 20:42:24 +0000 UTC2020-03-07 20:42:24 +0000 UTC

帮助解决python问题

  • 772

编写一个程序，将传统硬币“抛”100 次，并报告出现正面的次数和反面的次数。问题是我不知道如何正确显示所有一百次“投掷”的总和，我在这里写了一些东西，告诉我我是否认为正确，并且仍然帮助我这样做）如果你能建议一个就好了有这样的谜题的网站。

coin= random.randint(1,2)
tries=1
side1=""
side2=""


while not tries == 100:
    side1=int()
    side2=int()
    coin= random.randint(1,2)
    tries = tries + 1
    if coin ==1:
        side1=coin+side1
    elif coin ==2:
        side2=coin+side2
        side2=int(side2/2)
    print(coin, side1, side2)
python

3 个回答

  1. 试试这样：

    from random import randint

tries = 100
list_coin = []

while tries:
    list_coin.append(randint(1, 2))
    tries -= 1

print('рел - {}, решка - {}'.format( list_coin.count(1), list_coin.count(2)))
    • 1

  2. 有可能是这样的：

    from random import randint

heads = 0 # сколько раз выпал "орел"
tries = 100 # кол-во попыток
for _ in range(tries):
    # 0 - решка, 1 - орел
    if randint(0,1):
        heads +=1
tails = tries - heads # сколько раз выпала "решка"
print("Орёл: ", heads)
print("Решка: ", tails)
    • 0
  3. Best Answer
    import random
tries = 0
eagle = 0
tail = 0

while tries < 100:
    coin = random.randint(0, 1)
    tries += 1
    if coin > 0:
        eagle +=1
    elif coin < 1:
        tail += 1
print(f"Монета подброшена {tries} раз")
print(f"Орел {eagle}")
print(f"Решка {tail}")
    • 0

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