嗯，有很多方法。我将在 C++ 中给出示例。

• 在循环中，增加一个变量并立即减少它：

for (int i = 0; i < 1; i++) {
    cout << "О как могу! \n";
    i--;
}

• 创建一个不更改变量但分配它的循环：

for (int i = 0; i < 1; i = 0) {ляляля}

或者

for (bool i = true; i == true; i = true) {тра-ля-ля}

• 下一个选项是简单地跳过 for 循环中可能发生的所有事情：

for (;;) {
    cout << "Супермощь!\n";
}

• 我将给出的最后一个选项：朝错误的方向前进，因此条件将始终为真：

for (int i = 0; i < 1; i--) {
    cout << "To infinity and beyond!";
}

祝你好运！

#include <iostream>

#define continue goto my_for
#define for my_for:

int main()
{
    for
    {
        std::cout << "Hello" << std::endl;
        continue;
    }
    return 0;
}

为什么不for呢？;)

^{适用于 18 岁以上人士的内容。可能会有愤怒和暴力的爆发。不建议孕妇和老人服用。}

由于尚不知道编程语言，所以让它成为 Python：

for _ in iter(int, 1): 
    pass

好吧，你可以尝试这样的事情：

#include <iostream>
int main () {

    int j = 1;

    for (int i = 0; i!=j; ++i){
        std::cout << "Гони зачет!" << endl;
        i = 0; 

    }

    return 0;
}

让我们给她一个惊喜，用一个空的 main() 终止程序；

struct A
{
    A(){for(;;);}
};

static A a;

int main() 
{
    return 0;
}

所以你可以画一个迷宫：

#include <iostream>
struct A
{
    A(){for(;;std::cout<<(1&rand()?'\\':'/'));}
};

static A a;

int main() 
{
    return 0;
}

\//\\\\/\/\\\\\\//\//\//\///\//\\\////\\///\//\/////\//\\\\/\/\/\
/\\//\//\//\\//\\//\\\//\\\\////\\/\/\\/\/\//\\\/\\\\\\///\\/\\\/
//\\/\//////\///\\\//\\///\\\//\\\/\//\//\/\\///\\\\\//\/\\\\/\\/
////\/\\//\\\//\//\\\/\/\\/\\/\\/\\\\\\\\/\//\\\\////\//\/\///\\\
/\/\/\\\\/\/\//\\/\\///\//\\\\////\/\\//\\//\/\/\//\//\/////\//\\
\////\\\\\//\\\\\//\\/\//\\\\\/\\/\\\\/\//\\\/\//\\/\\///\\//\\\\
//\\///\\\/\/\\\/\\\\\/\//\\\\/\\\\/\\\//\\\/\/\/\////\///\\\/\\\
/\\\/\\\\///\\//\/\/\\//\/\\\//\\\/\\\\//\/\//\\\/\////\///\/////
/\\\/\\\\/\\/\///\//\\/\\\//\//\\\\///\\\\/\/\\///\\\\\\\\\/\\///
\//\/\/\\\\/\\/\////\\\//\\\\\\//\////\////\\\//\////\///\///\//\

C++

#include <iostream>

int main(){
    for (unsigned char i = 0; i < 256; ++i)
        std::cout << i;
}

c类语言：

for (;;);

嗯，老师

Python（来源）：

def zero_to_infinity():
    i = 0
    while True:
        yield i
        i += 1

for x in zero_to_infinity():
    print(x)

l = [1]
for x in l:
    l.append(x + 1)
    print(x)

通过定义清空 main

#define return for (;;);

int main()
{
    return 0;
}