主页 / 问题 / 1200925
Accepted
gfd2
Asked:2021-11-06 21:40:25 +0000 UTC2021-11-06 21:40:25 +0000 UTC

Quartz.NET 不适用于实体框架

  • 772

如果我在OrderTime类中创建具有基的构造函数，则Execute方法将停止工作。谁知道如何解决这个问题？有可能以其他方式实现它。我在互联网上找不到解决方案。请帮帮我。班级OrderTime

public class OrderTime : IJob
    {
        AppDBContent appDBContent;
        public OrderTime(AppDBContent appDBContent)
        {
            this.appDBContent = appDBContent;
        }
        public async Task Execute(IJobExecutionContext context)
        {
            var order = appDBContent.Order.FirstOrDefault(e => e.Id == 52);
            if (order != null)
            {
                order.Mail = "admin";
            }
            appDBContent.Order.Update(order);
            appDBContent.SaveChanges();
        }
    }

数据库类AppDBContent

public class AppDBContent : IdentityDbContext<User>
    {

        public AppDBContent(DbContextOptions<AppDBContent> options) : base(options)
        {
            //Database.EnsureCreated();
        }

        public override DbSet<User> Users { get; set; }
        public DbSet<Book> Book { get; set; }
        public DbSet<Сategories> Categories { get; set; }
        public DbSet<BookItems> LibraryBookItem { get; set; }
        public DbSet<Order> Order { get; set; }
        public DbSet<OrderDetail> OrderDetail { get; set; }

    }
c#

1 个回答

  1. Best Answer

    创建Jobwhich 的问题没有默认构造函数，但具有某种依赖关系，例如 on DbContext，可以使用包解决：Quartz.Extensions.DependencyInjection如果您使用ASP.NET Core.

    您Startup.cs将需要添加如下代码：

    services.AddQuartz(q =>
{
    // при помощи этого метода Job резолвится через контейнер,
    // а не создаваться через встроенную фабрику Quartz,
    // которая требует пустой конструктор
    q.UseMicrosoftDependencyInjectionScopedJobFactory();

    q.AddJob<OrderTime>(options =>
    {
        options.WithIdentity("trigger1", "group1")
            .Build();
    });

    q.AddTrigger(options =>
    {
        options.ForJob("trigger1", "group1")
            .StartNow()
            .WithSimpleSchedule(x =>
                x.WithIntervalInSeconds(2)
                    .RepeatForever());
    });
});

services.AddQuartzServer(options =>
{
    options.WaitForJobsToComplete = true;
});

    文档

    • 2

相关问题