如何绘制周名称与数值

我完全不记得带纵坐标的横坐标是谁，所以这里有两个放置选项。通过Seaborn一切都立即完成。原则上，他Pandas也知道如何自己绘制所有内容，但是那里的参数不直观，我不记得了。

import pandas as pd
import seaborn as sns

df = pd.read_csv('weekday_day_visits.csv')
sns.barplot(x = 'visits', y = 'weekday', data = df);

变体x和y：

sns.barplot(x = 'weekday', y = 'visits', data = df);

更新：

根据您的代码添加了带有直方图的变体：

import itertools
df['day_weekday'] = [w + '_' + str(d) for (w, d) in itertools.zip_longest(df['weekday'], df['day'])]
plt.figure(figsize=(15,5))
sns.barplot(x = 'day_weekday', y = 'visits', data = df);
plt.xticks(
    rotation=45, 
    horizontalalignment='right',
    fontweight='light',
    fontsize='x-large'  
);

day_weekday = pd.read_csv('weekday_day_visits.csv')

#создаём столбец day_weekday и заполняем его
day_weekday['day_weekday'] = day_weekday['weekday']
import itertools
day_weekday['day_weekday'] = [w + '_' + str(d) for (w, d) in \
        itertools.zip_longest(day_weekday['weekday'], day_weekday['day'])]

plt.close('all')
#figsize=(12,5) - размеры холста
fig, ax = plt.subplots(1, figsize=(12,5))
ax.plot(day_weekday['day_weekday'], day_weekday['visits'])

#повернуть подписи по оси x
fig.autofmt_xdate()