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Accepted
Kabdolla Meirambek
Asked:2021-12-31 20:06:41 +0000 UTC2021-12-31 20:06:41 +0000 UTC

对列表列表中的所有值求和

  • 772
Scores=[['4840'], ['3496', '2376'], ['1594'], ['871', '1869'], ['8915', '2398', '5663'], ['691', '9144'], ['7865'], ['6322', '9130', '1362'], ['1562'], ['2161', '1331'], ['8033', '8118', '2342'], ['1042', '1717'], ['5177', '6470'], ['5299'], ['4623', '6579', '8083'], ['7531', '1097'], ['6483', '6167', '6027'], ['3929', '3845', '7326'], ['8088', '5322'], ['5667', '7433', '8428'], ['1364'], ['2989', '4879'], ['4713', '2923'], ['8123', '7604', '153'], ['8285', '627', '2317'], ['9380', '3851'], ['6351', '8575'], ['4'], ['736'], ['979', '9346'], ['8778', '3565', '9234'], ['8939'], ['4358'], ['413', '5751', '4369'], ['1700', '9680', '5889'], ['159', '1946'], ['7488', '3845', '3445'], ['5172', '7039', '3127'], ['4', '3'], ['42']]

print([sum(i[2:6]) for i in Scores])
python

3 个回答

  1. 如果您需要找到每个列表中数字的总和，那么可以；

    print([sum(int(el) for el in i) for i in Scores])

    如果您需要找到所有值的总和，那么可以；

    print(sum(int(el) for i in Scores for el in i))
    • 3

  2. 所有值的总和：

    Scores = [['4840'], ['3496', '2376'], ['1594'], ['871', '1869'], ['8915', '2398', '5663'], ['691', '9144'], ['7865'],
          ['6322', '9130', '1362'], ['1562'], ['2161', '1331'], ['8033', '8118', '2342'], ['1042', '1717'],
          ['5177', '6470'], ['5299'], ['4623', '6579', '8083'], ['7531', '1097'], ['6483', '6167', '6027'],
          ['3929', '3845', '7326'], ['8088', '5322'], ['5667', '7433', '8428'], ['1364'], ['2989', '4879'],
          ['4713', '2923'], ['8123', '7604', '153'], ['8285', '627', '2317'], ['9380', '3851'], ['6351', '8575'], ['4'],
          ['736'], ['979', '9346'], ['8778', '3565', '9234'], ['8939'], ['4358'], ['413', '5751', '4369'],
          ['1700', '9680', '5889'], ['159', '1946'], ['7488', '3845', '3445'], ['5172', '7039', '3127'], ['4', '3'],
          ['42']]

general_sum = sum(sum(map(int, values)) for values in Scores)
print(general_sum)
    • 1
  3. Best Answer

    方式1：

    print(sum(sum(int(i) for i in obj) for obj in Scores))

    方式2：

    print(sum(sum(map(int, obj)) for obj in Scores))

    方式3：

    print(sum(map(lambda obj: sum(map(int, obj)), Scores)))

    方法4：变态和异国情调:)

    print(eval(str(Scores).replace(',', '').replace('\'', '').replace('[', '').replace(']', '').replace(' ', '+')))

    方法5：同样的变态，但更短:)

    import re

print(eval(re.sub('[,\'\[\]]', '', str(Scores)).replace(' ', '+')))
    • 0

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