主页 / 问题 / 1433225
Accepted
Nommad
Asked:2022-07-26 20:21:32 +0800 CST2022-07-26 20:21:32 +0800 CST

将列表拆分成对

  • 772
ListWithCortege = [(2, 4, 2, 1, 0), (4, 2, 1, 0), (1, 1, 0), (4, 1), (1, 4, 1)]
for item in ListWithCortege:
    print(item)
    for element in item[0:2]:
        print(element)
dict = {
(2,4):'1',
(4,2):'2',
(2,1):'3',
(1,0):'4',
(1,1):'5',
(4,1):'6'
}

结论：

(2, 4, 2, 1, 0)
2
4
(4, 2, 1, 0)
4
2
(1, 1, 0)
1
1
(4, 1)
4
1
(1, 4, 1)
1
4

请告诉我如何从元组的元素中获取交替的数字对？ [((2,4),(4,2),(2,1),(1,0)), ((4,2),(2,1),(1,0)), ((1,1),(1,0)), (4,1), ((1,4),(4,1)) )] 然后可以将它们与字典键的值进行比较吗？

python

1 个回答

  1. Best Answer

    您可以使用zip：

    ListWithCortege = [(2, 4, 2, 1, 0), (4, 2, 1, 0), (1, 1, 0), (4, 1), (1, 4, 1)]

result = []
for cort in ListWithCortege:
    result.append(tuple(zip(cort, cort[1:])))

print(result)

    UPD（如果列表中有数字则有效

    for cort in ListWithCortege:
    try:
        result.append(tuple(zip(cort, cort[1:])))
    except TypeError:
        result.append(tuple([cort])) # тут напишите действия, которые нужно сделать, если элемент один.

    UPD 2通过添加配对值来处理单例元组：

    for cort in ListWithCortege:
    if len(cort)==1:
        result.append(tuple((cort[0], -1)))
    else:
        result.append(tuple(zip(cort, cort[1:])))
    • 2

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