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Accepted
Павел Ромадов
Asked:2022-07-27 18:06:31 +0800 CST2022-07-27 18:06:31 +0800 CST

将 javascript 代码重写为 jQuery

  • 772
const navigateToFormStep = (stepNumber) => {
  document.querySelectorAll(".form-step").forEach((formStepElement) => {
      formStepElement.classList.add("d-none");
  });
  document.querySelectorAll(".form-stepper-list").forEach((formStepHeader) => {
      formStepHeader.classList.add("form-stepper-unfinished");
      formStepHeader.classList.remove("form-stepper-active", "form-stepper-completed");
  });
  document.querySelector("#step-" + stepNumber).classList.remove("d-none");
};

document.querySelectorAll(".btn-navigate-form-step").forEach((formNavigationBtn) => {
  formNavigationBtn.addEventListener("click", () => {
      const stepNumber = parseInt(formNavigationBtn.getAttribute("step_number"));
      navigateToFormStep(stepNumber);
  });
});

我尝试自己重写它，我认为我犯了很多错误。虽然控制台不发誓。

 function navigateToFormStep($stepNumber) {
$('.form-step').each(($formStepElement), function(){
  $formStepElement.addClass('d-none')
})

$('.form-stepper-list').each(($formStepHeader), function(){
  $formStepHeader.addClass('form-stepper-unfinished')
  $formStepHeader.removeClass('form-stepper-unfinished')
  $formStepHeader.removeClass('form-stepper-completed')
})
$('#step-' + $stepNumber).removeClass('d-none')

}

 (function($){
$('.btn-navigate-form-step').each(($formNavigationBtn), function() {
  $formNavigationBtn.on('click', function(){
   var stepNumber = parseInt($formNavigationBtn.attr('step_number'))
    navigateToFormStep($stepNumber)
 })
})

})

而且代码现在不起作用。也许犯了一些严重的错误。我试图编辑每一行js代码并将其翻译成jquery。

javascript

2 个回答

  1. 与@Jean-Claude 相同，只有 10 行。

    function navToF(nStep) {
  $(".form-step").addClass("d-none");
  $(".form-stepper-list").addClass("form-stepper-unfinished");
  $(".form-stepper-list").removeClass("form-stepper-active form-stepper-completed");
  $("#step-" + nStep).removeClass("d-none");
}

$(".btn-navigate-form-step").on('click',function(){
  const nStep = parseInt($(this).attr("step_number"));
  navToF(nStep);
})
    • 2
  2. Best Answer

    你误读了each()函数的描述，你认为 each() 有两个参数，但实际上一个参数是一个有两个参数的函数。

    .each( function )

function
Type: Function( Integer index, Element element )
A function to execute for each matched element.

    我添加了一些更多的优化，你可以使用它来访问元素，在用 jquery 包装它之后，代码如下：

    function navigateToFormStep(stepNumber) {
  $('.form-step').each(function() {
    $(this).addClass('d-none')
  });

  $('.form-stepper-list').each(function() {
    $(this).addClass('form-stepper-unfinished')
    $(this).removeClass('form-stepper-active')
    $(this).removeClass('form-stepper-completed')
  });

  $('#step-' + stepNumber).removeClass('d-none');
}


$('.btn-navigate-form-step').each(function() {
  $(this).on('click', function() {
    var stepNumber = parseInt($(this).attr('step_number'));
    console.log(stepNumber);
    navigateToFormStep(stepNumber);
  })
})
    div {
  border: 1px solid grey;
  margin: 2px;
}

.d-none {
  border: 0;
}

.form-stepper-unfinished {
  border: 1px solid red;
}
    <script src="https://code.jquery.com/jquery-3.1.0.js"></script>
<div class="form-step">form-step</div>
<div class="form-stepper-list">
  <div id="step-1" class="d-none">step-1</div>
  <div id="step-2" class="d-none">step-2</div>
</div>
<button class="btn-navigate-form-step" step_number="1">button1</button>
<button class="btn-navigate-form-step" step_number="2">button2</button>

    • 0

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