Map<String, Map<String, Set<String>>> [关闭]

首先收集第一个Map1 keyWordMap.put(currentKey, new HashSet<>());

在第二个 Map2 中传递 key(namesMachine = String) 并作为值 new HashMap unityTableWithNameMachine.put(namesMachine, new HashMap<>()); 然后我调用 Map2 并从那里获取 Map1 密钥并开始使用它，写下我的数据 unityTableWithNameMachine.get(namesMachine).put(currentKey,keyWordMap.get(currentKey))

下面是结果的方法（字表解析器） ps 对不起代码）

  @SneakyThrows
  private void parseListOfWorksTable(XWPFTable table, Map<String, Set<String>> keyWordMap,
      Map<String, Map<String, Set<String>>> unityTableWithNameMachine) {
    String currentKey = null;

    for (var row : table.getRows()) {
      if (helperForParser.cellValueContains(row, 0, "станок")) {
        continue;
      }
      if (row.getTableCells().size() == 1) {
        if (!row.getCell(0).getText().contains("MIKRON ")) {
          currentKey = row.getCell(0).getText();
          currentKey = currentKey.replace("\n", "").trim();

          putKeyWordMap(currentKey, keyWordMap);
          putUnityTableWithNameMachine(namesMachine, unityTableWithNameMachine);
          continue;
        }

      } else if (row.getTableCells().size() > 2) {
        var keyWordPosition = helperForParser.getKeyWordPosition(row);
        if (keyWordPosition >= 0) {
          currentKey = row.getCell(keyWordPosition).getText();
          if (currentKey == null || currentKey.isEmpty()) {
            continue;
          }

          putKeyWordMap(currentKey, keyWordMap);
          putUnityTableWithNameMachine(namesMachine, unityTableWithNameMachine);
          continue;
        }
      }
      if (currentKey == null || currentKey.isEmpty()) {
        continue;
      }
      if (!row.getCell(0).getText().isEmpty()) {
        keyWordMap.get(currentKey)
            .add(row.getCell(0).getText().replace("\n", "").replace(";", "").trim());

        unityTableWithNameMachine.get(namesMachine)
            .put(currentKey, keyWordMap.get(currentKey));
      }
    }
  }