主页 / 问题 / 1479941
Accepted
S_Smerch
Asked:2022-12-21 22:33:54 +0800 CST2022-12-21 22:33:54 +0800 CST

超时在 discord.py 中不起作用

  • 772

一个机器人中有一个现成的命令，它可以工作。当我尝试为第二个机器人编写它时，它显示错误：

Command raised an exception: TypeError: timeout() got some positional-only arguments passed as keyword arguments: 'until'

这是命令本身：

@bot.command(aliases=['mute', 'мут', 'мьют', 'timemute'])
@commands.has_permissions(kick_members=True)
async def timeout(ctx, member: discord.Member, time=None, *, reason=None):
    author = ctx.author
    if member != None:
        if time != None:
            t = humanfriendly.parse_timespan(time)
            await member.timeout(until = discord.utils.utcnow() + datetime.timedelta(seconds=t), reason=reason)
            if reason != None:
                embed = discord.Embed(
                    title = 'Mute ✅',
                    description = f'**{member.mention}**  успешно  замучен  на  **{time}**\n\n**Причина: `{reason}`**',
                    colour = discord.Colour.from_rgb(0, 189, 0)
                )        
                await ctx.send(embed=embed) #await ctx.send (f'**{member.mention}** был замучен на **{time}** по причине **"{reason}"**')
            else:
                embed = discord.Embed(
                    title = 'Mute ✅',
                    description = f'**{member.mention}**  успешно  замучен  на  **{time}**',
                    colour = discord.Colour.from_rgb(0, 189, 0)
                )        
                await ctx.send(embed=embed) #await ctx.send (f'**{member.mention}** был замучен на **{time}**')
        else:
            embed = discord.Embed(
                title = 'Mute ❌',
                description = f'{author.mention}  укажите  время  наказания',
                colour = discord.Colour.from_rgb(171, 0, 0)
            )        
            await ctx.send(embed=embed)
    else:
        embed = discord.Embed(
            title = 'Mute ❌',
            description = f'{author.mention}  укажите  кого  нужно  наказать',
            colour = discord.Colour.from_rgb(171, 0, 0)
        )        
        await ctx.send(embed=embed)

问题是什么以及如何解决？

python

1 个回答

  1. Best Answer

    还没有做任何超时，但我测试了你的代码并通过删除 until 值来修复它：

    await member.timeout(datetime.timedelta(seconds=t), reason=reason)

    所以代码可以正常工作并使用户感到困惑。

    测试。

    完整代码：

    @bot.command(aliases=['mute', 'мут', 'мьют', 'timemute'])
@commands.has_permissions(kick_members=True)
async def timeout(ctx, member: discord.Member, time=None, *, reason=None):
    author = ctx.author
    if member != None:
        if time != None:
            t = humanfriendly.parse_timespan(time)
            await member.timeout(datetime.timedelta(seconds=t), reason=reason)
            if reason != None:
                embed = discord.Embed(
                    title = 'Mute ✅',
                    description = f'**{member.mention}**  успешно  замучен  на  **{time}**\n\n**Причина: `{reason}`**',
                    colour = discord.Colour.from_rgb(0, 189, 0)
                )        
                await ctx.send(embed=embed) #await ctx.send (f'**{member.mention}** был замучен на **{time}** по причине **"{reason}"**')
            else:
                embed = discord.Embed(
                    title = 'Mute ✅',
                    description = f'**{member.mention}**  успешно  замучен  на  **{time}**',
                    colour = discord.Colour.from_rgb(0, 189, 0)
                )        
                await ctx.send(embed=embed) #await ctx.send (f'**{member.mention}** был замучен на **{time}**')
        else:
            embed = discord.Embed(
                title = 'Mute ❌',
                description = f'{author.mention}  укажите  время  наказания',
                colour = discord.Colour.from_rgb(171, 0, 0)
            )        
            await ctx.send(embed=embed)
    else:
        embed = discord.Embed(
            title = 'Mute ❌',
            description = f'{author.mention}  укажите  кого  нужно  наказать',
            colour = discord.Colour.from_rgb(171, 0, 0)
        )        
        await ctx.send(embed=embed)
    • 1

相关问题