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Accepted
Михаил Горячев
Asked:2023-02-02 20:40:07 +0800 CST2023-02-02 20:40:07 +0800 CST

在php中提交表单和文件

  • 772

告诉我出了什么事？我通过 ajax 将表单发送给处理程序：

<form id="sendmsg" method="POST" enctype="multipart/form-data">

<!-- фотка -->
    <input type="file" name="images[]" id="files">
    <button class="uk-button uk-button-secondary"><?echo $lang->selectphoto;?></button>
<!-- фотка -->

<textarea id="textarea" class="uk-textarea standart" name="message" maxlength="1500" required></textarea>

<input type="submit" name="send" value="&#10148;" class="uk-button uk-button-secondary send-button" id="sendbtn">

</form>

阿贾克斯：

<script>
    $(document).ready( function() { 
    $("#sendmsg").submit(function(send){
        send.preventDefault();
        $.ajax({
            url: 'updates/sendmsg.php',
            type: 'POST',
            data: {'files': $('#files')[0].files[0],'idtodb':'<?php echo $partnerid ?>', 'message':$('textarea[name="message"]').val()},
            success: function(html){  
                document.getElementById("sendmsg").reset();
                $("#globalresult").html(html);
            }  
        });
    });
    });
</script>

不选择照片，一切正常，但如果你选择照片，控制台会发誓：

jquery.min.js:2 Uncaught (in promise) TypeError: Failed to execute 'arrayBuffer' on 'Blob': Illegal invocation
    at i (jquery.min.js:2:73313)
    at Dt (jquery.min.js:2:73205)
    at Dt (jquery.min.js:2:73228)
    at S.param (jquery.min.js:2:73524)
    at Function.ajax (jquery.min.js:2:76904)
    at HTMLFormElement.<anonymous> (chat?id=23:509:11)
    at HTMLFormElement.dispatch (jquery.min.js:2:43090)
    at v.handle (jquery.min.js:2:41074)
php

1 个回答

  1. Best Answer

    使用 FormData 对象。或多或少是这样的：

    <script>
    $(document).ready( function() { 
    $("#sendmsg").submit(function(send){
        send.preventDefault();
        var formData = new FormData;
        formData.append('files', $('#files')[0].files[0]);
        formData.append('idtodb', '<?php echo $partnerid ?>');
        formData.append('message', $('textarea[name="message"]').val());
        $.ajax({
            url: 'updates/sendmsg.php',
            type: 'POST',
            data: formData,
            success: function(html){  
                document.getElementById("sendmsg").reset();
                $("#globalresult").html(html);
            }  
        });
    });
    });
</script>
    • 1

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