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Accepted
Leks
Asked:2023-09-30 16:32:05 +0800 CST2023-09-30 16:32:05 +0800 CST

按键翻转不起作用

  • 772

document.addEventListener('keydown', e => {
    if (e.code == 'KeyW' && e.code == 'KeyQ') {
        console.log('yes')
    };
})

javascript

1 个回答

  1. Best Answer

    您必须检查所需的击键，当它们匹配时将它们记住在一个数组中，然后检查所需的数字。learn.javascript.ru 上有关于此信息以跟踪同时按下

    let keys = [];
let res = document.querySelector('.result');
document.addEventListener('keydown', function(event) {
  if (event.code == 'KeyQ' || event.code == 'KeyZ') {
    keys.push(event.code)
  }
  if (keys.includes('KeyQ') && keys.includes('KeyZ') ) {
    res.innerHTML = 'yes';
  }
});
document.addEventListener('keyup', function(event) {
  keys.length = 0;
  res.innerHTML = '';
});
    <div class="result"></div>

    • 0

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