提取查询左加入休眠

有一个表users&words多对多的关系。还有一个链接表，嗯，例如users_words（出乎意料，对吧？）你如何Criteria在以下帮助下做出这样的选择：

select * 
from words 
left join users_words on users_words.word_id = words.id
where users_words.user_id = {id} or 
      users_words.id is null'

据我了解它hibernate连接通过inner join但我需要left。

public class Group implements DomainModel{

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    private Long id;

    ...

    @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.REFRESH)
    @JoinTable(name = "user_groups", joinColumns = {
            @JoinColumn(name = "group_id") },
            inverseJoinColumns = { @JoinColumn(name = "user_id") })
    private Set<User> users = new HashSet<User>(0);
}

public class User implements DomainModel{

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id")
    private Long id;

    ...

    @ManyToMany(fetch = FetchType.LAZY, mappedBy = "users")
    private Set<Group> groups = new HashSet<Group>(0);
}
{
    Criteria criteria = session.createCriteria(Group.class);
    criteria.setFetchMode("users", FetchMode.JOIN);
    criteria.createAlias("users","usersAlias");
    criteria.add(Restrictions.isNull("users.id"));
}