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Accepted
Gayrat Vlasov
Asked:2020-03-26 22:12:59 +0000 UTC2020-03-26 22:12:59 +0000 UTC

存储大小未知

  • 772

我决定将许多参数设置为数组，其长度可以不同。

为了访问其中一个参数数组，我定义了一个变量，我将其中一个数组的地址分配给该变量：float * curTimeInterval[]; 编译时出现错误：存储大小未知

请教如何用参数选择所需的数组并从中提取值？

static float TimeImterval1[] PROGMEM = {0.2,0.2,0.2,2};
static int TimeImterval1N PROGMEM = 4;
static float TimeImterval2[] PROGMEM = {0.2,0.2,0.2,0.5,0.2,2};
static int TimeImterval2N PROGMEM = 6;

float * curTimeInterval[];
int curLength;

 _ticker.detach();

switch (curTickPGM)
{
  case 2:
    curTimeInterval = &TimeImterval2;
    curLength = TimeImterval2N;
    break;

  default:
    curTimeInterval = &TimeImterval1;
    curLength = TimeImterval1N;
    break;
}
c++

2 个回答

  1. Best Answer

    而背后隐藏着PROGMEM什么？

    所以 - 一切都很简单：

    static float TimeImterval1[] = {0.2f,0.2f,0.2f,2f};
static int TimeImterval1N = size(TimeImterval1);
static float TimeImterval2[] = {0.2f,0.2f,0.2f,0.5f,0.2f,2f};
static int TimeImterval2N = size(TimeImterval2);


float * curTimeInterval;


    case 2:
        curTimeInterval = TimeImterval2;
        curLength = TimeImterval2N;
        break;

    default:
        curTimeInterval = TimeImterval1;
        curLength = TimeImterval1N;
        break;
    • 2

  2. 删除括号。

    float * curTimeInterval;
    • 2

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