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Teemitze
Asked:2020-05-22 18:11:41 +0000 UTC2020-05-22 18:11:41 +0000 UTC

如何获取默认值？

  • 772

如何获得默认值（28）？这是 github 上更完整的代码https://github.com/Teemitze/test

    package ru.otus.spring01.dao;

    import ru.otus.spring01.domain.Person;

    public class PersonDaoSimple implements PersonDao {

        public Person findByName(String name) {
            return new Person(name, 18);
        }

        public void setDefaultAge(String defaultAge) {
        }
    }

春天.xml


        <?xml version="1.0" encoding="UTF-8"?>
        <beans xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
               xmlns="http://www.springframework.org/schema/beans"
               xsi:schemaLocation="http://www.springframework.org/schema/beans
                http://www.springframework.org/schema/beans/spring-beans.xsd">


            <bean id="personDao" class="ru.otus.spring01.dao.PersonDaoSimple">
                <property name="defaultAge" value="28"/>
            </bean>

            <bean id="personService" class="ru.otus.spring01.service.PersonServiceImpl">
                <constructor-arg name="dao" ref="personDao"/>
            </bean>

    </beans>
java

1 个回答

  1. Best Answer

    正如评论中已经写的那样，您需要初始化字段并通过setter将值从xml传递给它

    public class PersonDaoSimple implements PersonDao {
    private int defaultAge=18;

    public Person findByName(String name) {
        return new Person(name, defaultAge);
    }

    public void setDefaultAge(int defaultAge) {
    this.defaultAge=defaultAge;
    }
}
    • 1

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