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主页 / 问题 / 985394
Accepted
Vitaly M.
Vitaly M.
Asked:2020-05-25 16:55:51 +0000 UTC2020-05-25 16:55:51 +0000 UTC 2020-05-25 16:55:51 +0000 UTC

spring-webmvc.xml 配置

  • 772

帮助配置 Spring。

控制器

@Controller
@RequestMapping("/*")
public class IndexController {

    private final Logger log = LoggerFactory.getLogger(this.getClass());

    @RequestMapping(method = RequestMethod.GET)
    public String printHello(HttpServletRequest request, Model model) {
...

存储库

@Repository
public class JpaRepositoryImpl implements JpaRepository {

    @PersistenceContext
    private EntityManager emf; // Для внедрения EntityManager
...

好吧,一堆其他必要的类

在 spring-db.xml 中连接的存储库

...
<context:component-scan base-package="ru.bityard.bitrix24.serverAuth.repository"/>
...

spring-mvc.xml 中连接的控制器和服务

...

    <context:component-scan base-package="ru.bityard.bitrix24.serverAuth.**.web"/>
    <context:component-scan base-package="ru.bityard.bitrix24.serverAuth.**.service"/>

    <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver">
        <property name="prefix" value="/WEB-INF/jsp/"/>
        <property name="suffix" value=".jsp"/>
    </bean>
...

我在 spring-app.xml 中收集所有其他 bean

这就是我试图在 web.xml 中组合的所有内容

<web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee"
         xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
         xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee
         http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
         version="3.1">

    <display-name>Spring MVC Application</display-name>

    <context-param>
        <param-name>contextClass</param-name>
        <param-value>
            org.springframework.web.context.support.AnnotationConfigWebApplicationContext
        </param-value>
    </context-param>

    <context-param>
        <param-name>contextConfigLocation</param-name>
        <param-value>
            classpath:spring-app.xml
            classpath:spring-db.xml
        </param-value>
    </context-param>

    <listener>
        <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
    </listener>

    <servlet>
        <servlet-name>index</servlet-name>
        <servlet-class>
            org.springframework.web.servlet.DispatcherServlet
        </servlet-class>
        <init-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>
                classpath:spring-mvc.xml
            </param-value>
        </init-param>
        <init-param>
            <param-name>throwExceptionIfNoHandlerFound</param-name>
            <param-value>true</param-value>
        </init-param>
        <init-param>
            <param-name>contextClass</param-name>
            <param-value>
                org.springframework.web.context.support.AnnotationConfigWebApplicationContext
            </param-value>
        </init-param>
        <load-on-startup>1</load-on-startup>
    </servlet>

    <servlet-mapping>
        <servlet-name>index</servlet-name>
        <url-pattern>/</url-pattern>
    </servlet-mapping>

</web-app>

我收到一个错误:

2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:DispatcherServlet.java:doService:891 - DispatcherServlet with name 'index' processing GET request for [/index.php]
2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:AbstractHandlerMethodMapping.java:getHandlerInternal:312 - Looking up handler method for path /index.php
2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:AbstractHandlerMethodMapping.java:getHandlerInternal:322 - Did not find handler method for [/index.php]
2019-05-25 11:48:00 WARN  http-nio-8080-exec-4:DispatcherServlet.java:noHandlerFound:1205 - No mapping found for HTTP request with URI [/index.php] in DispatcherServlet with name 'index'
2019-05-25 11:48:00 DEBUG http-nio-8080-exec-4:FrameworkServlet.java:processRequest:1000 - Successfully completed request

我的配置错误在哪里?

java
  • 2 2 个回答
  • 10 Views

2 个回答

  • Voted
  1. user236980
    2020-05-25T17:48:18Z2020-05-25T17:48:18Z

    替换@RequestMapping("/*")为@RequestMapping("/")- 星号是多余的。

    最好在方法之前指定这个注解,而不是整个类通用。

    最好在方法之前写:

    @RequestMapping({"/", "/index.html", "/index.php"})
    

    请参阅Spring 请求映射

    • 0
  2. Best Answer
    Vitaly M.
    2020-05-30T22:42:28Z2020-05-30T22:42:28Z

    我设法解决了这样的问题:

    我导入 spring-app.xml 的 spring-db.xml 和 spring-mvc.xml 文件

    弹簧应用程序.xml

    ...
        <import resource="spring-db.xml"/>
        <import resource="spring-mvc.xml"/>
    ...
    

    并像这样设置调度程序

    web.xml

    ... 
        <context-param>
            <param-name>contextClass</param-name>
            <param-value>
                org.springframework.web.context.support.XmlWebApplicationContext
            </param-value>
        </context-param>
    
        <context-param>
            <param-name>contextConfigLocation</param-name>
            <param-value>
                classpath:spring-app.xml
            </param-value>
        </context-param>
    
        <listener>
            <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
        </listener>
    
        <servlet>
            <servlet-name>mvc-despetcher</servlet-name>
            <servlet-class>
                org.springframework.web.servlet.DispatcherServlet
            </servlet-class>
              <init-param>
                <param-name>contextConfigLocation</param-name>
                <param-value>
                    classpath:spring-app.xml
                </param-value>
            </init-param>
    
            <init-param>
                <param-name>throwExceptionIfNoHandlerFound</param-name>
                <param-value>true</param-value>
            </init-param>
            <init-param>
                <param-name>contextClass</param-name>
                <param-value>
                    org.springframework.web.context.support.XmlWebApplicationContext
                </param-value>
            </init-param>
            <load-on-startup>1</load-on-startup>
        </servlet>
    
        <servlet-mapping>
            <servlet-name>mvc-despetcher</servlet-name>
            <url-pattern>/</url-pattern>
        </servlet-mapping>
    ...
    

    收割机开始了……

    • 0

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