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Руслан Мамедов
Asked:2020-11-24 16:47:15 +0000 UTC2020-11-24 16:47:15 +0000 UTC

用 C 语言与学生一起创建结构数组

  • 772

创建将学生添加到结构数组的函数时，以红色突出显示。这是整个代码

#include <stdio.h>
#include <string.h>
#include <locale.h>


struct addStudent(char name[], unsigned int age, unsigned int course, unsigned int);

struct student {
    char name[50];
    unsigned int age;
    unsigned int course;
};

unsigned int student_counter = 0;

int main(void) {
    setlocale(LC_ALL, "Rus");

    struct student st[20];

    strcpy_s(st[0].name, 50, "Руслан");
    st[0].age = 18;
    st[0].course = 1;
    student_counter += 1;

    for (int i = 0; i < student_counter; i++) {
        printf("%s \t %d курс \t  %d лет \n", st[i].name, st[i].course, st[i].age);
    }
    _getch();
    return 0;
}

struct addStudent(char name[], unsigned age, unsigned course, unsigned age){
    student res_st;
    scrcpy_s(res_st, 50, name);



}

为什么我不能创建 addStudent 函数？提前致谢。

c

1 个回答

  1. Best Answer

    你应该看看指针和内存分配

    这是一个工作示例：

    #include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <locale.h>

struct student *addStudent(char *name, unsigned int age, unsigned int course);

struct student {
    char name[50];
    unsigned int age;
    unsigned int course;
};

unsigned int student_counter = 0;

int main(void) {
    setlocale(LC_ALL, "Rus");

    struct student *st[20];

    st[0] = addStudent("Руслан", 18, 1);
    student_counter += 1;

    for (int i = 0; i < student_counter; i++) {
        printf("%s \t %d курс \t  %d лет \n", st[i]->name, st[i]->course, st[i]->age);
    }

    return 0;
}

struct student *addStudent(char *name, unsigned int age, unsigned int course) {
    struct student *res_st = malloc(sizeof(struct student));
    strcpy(res_st->name, name);
    res_st->age = age;
    res_st->course = course;

    return res_st;
}

    并且您无法创建 addStudent 函数，因为：

    • 在unsigned之后的函数参数中，需要写数据类型int

    • 您不会返回您创建的结构，它是在函数内部创建的，完成后它会消失

    • 年龄声明在参数中重复

    • 0

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