主页 / 问题 / 1051419
Accepted
Alexei Polovin
Asked:2020-11-27 23:38:25 +0000 UTC2020-11-27 23:38:25 +0000 UTC

如何将矩阵行绑定到键？在这种情况下，变量单元格被返回

  • 772
unsigned short numberTable[WIDTH_HEIGHT][WIDTH_HEIGHT];
for(short i = 0;i<WIDTH_HEIGHT;i++){
    for(short j = 0;j<WIDTH_HEIGHT;j++){
        numberTable[i][j] = j+1;
    }
}
for( short i = 0;i<WIDTH_HEIGHT;i++){
    for(short j = 0;j<WIDTH_HEIGHT;j++){
        std::cout<<unsigned(numberTable[i][j]);
    }
    std::cout<<'\n';
}
std::map<short,unsigned short(*)[WIDTH_HEIGHT]> gameTable;
for(short i = 0;i<WIDTH_HEIGHT;i++){
    gameTable[i+1] = &numberTable[i];  
}
std::map<short,unsigned short(*)[WIDTH_HEIGHT]>::iterator itr = gameTable.begin();
while(itr!=gameTable.end()){
    std::cout<<itr->second<<'\n';
    ++itr;
}
c++

3 个回答

  1. Best Answer
    std::map<short, unsigned short*> gameTable;
for (short i = 0; i < WIDTH_HEIGHT; i++) {
    gameTable[i + 1] = numberTable[i];
}
auto itr = gameTable.begin();
while (itr != gameTable.end()) {
    for (int i = 0; i < WIDTH_HEIGHT; ++i)
         std::cout << itr->second[i] << ' ';
    std::cout << '\n';
    ++itr;
}

    但是如果你要存储一个数组类型，那么itr->second这里就是数组的地址，解引用你会得到数组本身，你还需要访问这个数组的元素。意思是：

    std::map<short, unsigned short(*)[WIDTH_HEIGHT]> gameTable;
for (short i = 0; i < WIDTH_HEIGHT; i++) {
    gameTable[i + 1] = &numberTable[i];
}
std::map<short, unsigned short(*)[WIDTH_HEIGHT]>::iterator itr = gameTable.begin();
while (itr != gameTable.end()) {
    for(int i = 0; i < WIDTH_HEIGHT; ++i)
        std::cout << (*itr->second)[i] << ' ';
    cout << '\n';
    ++itr;
}
    • 2

  2. 存储另一个数组类型总是更好，我们在它的第二个（数组地址）中引用。并且您需要引用数组本身的元素。

    std::map<short, unsigned short(*)[WIDTH_HEIGHT]> gameTable;
for (short i = 0; i < WIDTH_HEIGHT; i++) {
    gameTable[i + 1] = &numberTable[i];
}
std::map<short, unsigned short(*)[WIDTH_HEIGHT]>::iterator itr = gameTable.begin();
while (itr != gameTable.end()) {
    for(int i = 0; i < WIDTH_HEIGHT; ++i)
        std::cout << (*itr->second)[i] << ' ';
    cout << '\n';
    ++itr;
}
    • 1

  3. 如果用户 Fameek不想重复我的部分答案，他可以写另一个选项，例如：

    std::map<short, unsigned short(*)[WIDTH_HEIGHT]> gameTable;
for (short i = 0; i < WIDTH_HEIGHT; i++) {
    gameTable[i + 1] = &numberTable[i];
}   
for (auto p : gameTable) {
    for (unsigned short el : *p.second) {
        std::cout << el << ' ';
    }
    std::cout << '\n';
}
    • 0

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