是否可以通过虚拟消除方法歧义？

#include <iostream>
using namespace std;

class Student
{
public:
    Student() {}
    ~Student() {}
    void show()
    {
        cout << "Name: " << name << endl;
        cout << "Surname: " << surname << endl;
        cout << "Group: " << group << endl;
    }
    void set_name(string Name) { name = Name; }
    void set_surname(string Surname) { surname = Surname; }
    void set_group(string Group) { group = Group; }
protected:
    string name, surname;
    string group;
};

class Teacher
{
public:
    Teacher() : salary(0) {}
    ~Teacher() {}
    void show()
    {
        cout << "Name: " << name << endl;
        cout << "Surname: " << surname << endl;
        cout << "Degree: " << degree << endl;
        cout << "Salary: " << salary << endl;
    }
    void set_name(string Name) { name = Name; }
    void set_surname(string Surname) { surname = Surname; }
    void set_degree(string Degree) { degree = Degree; }
    void set_salary(double Salary) { salary = Salary; }
protected:
    string name, surname;
    string degree;
    double salary;
};

class Undergraduate : public Student
{
public:
    Undergraduate() {}
    ~Undergraduate() {}
};

class Postgraduate: virtual public Undergraduate
{
public:
    Postgraduate() {}
    ~Postgraduate() {}
};

class TeachingAssistant: public Teacher, public Postgraduate
{
public:
    TeachingAssistant(){}
    ~TeachingAssistant(){}
};


int main()
{
    TeachingAssistant ta;
    ta.show();
}

在这样的一段代码中，需要消除方法显示的歧义，set_name_set_surname

似乎我试图vritual在几乎所有地方替换继承，但它仍然不起作用。据我所知，virtual当某些东西被继承两次但它是同一个基类的成员时，它有助于消除歧义。

如果virtual方法来自不同的类，但名称不同，会有帮助吗？如果没有，最好的方法是什么？