RError.com

RError.com Logo RError.com Logo

RError.com Navigation

  • 主页

Mobile menu

Close
  • 主页
  • 系统&网络
    • 热门问题
    • 最新问题
    • 标签
  • Ubuntu
    • 热门问题
    • 最新问题
    • 标签
  • 帮助
主页 / 问题 / 1080974
Accepted
r.mcreal
r.mcreal
Asked:2020-02-11 14:28:34 +0000 UTC2020-02-11 14:28:34 +0000 UTC 2020-02-11 14:28:34 +0000 UTC

symfony 授权时出错

  • 772

在命令的帮助下make:auth创建了授权。用用户填满表格。当我尝试登录时,我收到一条错误消息:

There is no user provider for user "App\Entity\User". Shouldn't the "supportsClass()" method of your user provider return true for this classname?

怎么了?似乎我按照文档https://symfony.com/doc/current/security/form_login_setup.html中的指示做了所有事情

我的安全.yaml

    encoders:
        App\Entity\User:
            algorithm: bcrypt
            cost: 12
    # https://symfony.com/doc/current/security.html#where-do-users-come-from-user-providers
    providers:
        in_memory: { memory: null }
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            anonymous: lazy
            guard:
                authenticators:
                    - App\Security\LoginFormAuthenticator
            logout:
                path: app_logout
                # where to redirect after logout
                # target: app_any_route

            # activate different ways to authenticate
            # https://symfony.com/doc/current/security.html#firewalls-authentication

            # https://symfony.com/doc/current/security/impersonating_user.html
            # switch_user: true

    # Easy way to control access for large sections of your site
    # Note: Only the *first* access control that matches will be used
    access_control:
        # - { path: ^/admin, roles: ROLE_ADMIN }
        # - { path: ^/profile, roles: ROLE_USER }

Guard(表单处理)


namespace App\Security;

use App\Entity\User;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Symfony\Component\Security\Core\Exception\CustomUserMessageAuthenticationException;
use Symfony\Component\Security\Core\Exception\InvalidCsrfTokenException;
use Symfony\Component\Security\Core\Security;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Csrf\CsrfToken;
use Symfony\Component\Security\Csrf\CsrfTokenManagerInterface;
use Symfony\Component\Security\Guard\Authenticator\AbstractFormLoginAuthenticator;
use Symfony\Component\Security\Guard\PasswordAuthenticatedInterface;
use Symfony\Component\Security\Http\Util\TargetPathTrait;

class LoginFormAuthenticator extends AbstractFormLoginAuthenticator implements PasswordAuthenticatedInterface
{
    use TargetPathTrait;

    private $entityManager;
    private $urlGenerator;
    private $csrfTokenManager;
    private $passwordEncoder;

    public function __construct(EntityManagerInterface $entityManager, UrlGeneratorInterface $urlGenerator, CsrfTokenManagerInterface $csrfTokenManager, UserPasswordEncoderInterface $passwordEncoder)
    {
        $this->entityManager = $entityManager;
        $this->urlGenerator = $urlGenerator;
        $this->csrfTokenManager = $csrfTokenManager;
        $this->passwordEncoder = $passwordEncoder;
    }

    public function supports(Request $request)
    {
        return 'app_login' === $request->attributes->get('_route')
            && $request->isMethod('POST');
    }

    public function getCredentials(Request $request)
    {
        $credentials = [
            'email' => $request->request->get('email'),
            'password' => $request->request->get('password'),
            'csrf_token' => $request->request->get('_csrf_token'),
        ];
        $request->getSession()->set(
            Security::LAST_USERNAME,
            $credentials['email']
        );

        return $credentials;
    }

    public function getUser($credentials, UserProviderInterface $userProvider)
    {
        $token = new CsrfToken('authenticate', $credentials['csrf_token']);
        if (!$this->csrfTokenManager->isTokenValid($token)) {
            throw new InvalidCsrfTokenException();
        }

        $user = $this->entityManager->getRepository(User::class)->findOneBy(['email' => $credentials['email']]);

        if (!$user) {
            // fail authentication with a custom error
            throw new CustomUserMessageAuthenticationException('Email could not be found.');
        }

        return $user;
    }

    public function checkCredentials($credentials, UserInterface $user)
    {
        return $this->passwordEncoder->isPasswordValid($user, $credentials['password']);
    }

    /**
     * Used to upgrade (rehash) the user's password automatically over time.
     */
    public function getPassword($credentials): ?string
    {
        return $credentials['password'];
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey)
    {
        if ($targetPath = $this->getTargetPath($request->getSession(), $providerKey)) {
            return new RedirectResponse($targetPath);
        }

        // For example : return new RedirectResponse($this->urlGenerator->generate('some_route'));
        //throw new \Exception('TODO: provide a valid redirect inside '.__FILE__);

        return new RedirectResponse($this->urlGenerator->generate('app_homepage'));


    }

    protected function getLoginUrl()
    {
        return $this->urlGenerator->generate('app_login');
    }
}

PS在此之前,我在 UserProvider 中编辑了supportsClass,使其不返回false:

{
    return $class === UserIdentity::class;
}
php
  • 1 1 个回答
  • 10 Views

1 个回答

  • Voted
  1. Best Answer
    Denis Startsev
    2020-02-11T22:58:41Z2020-02-11T22:58:41Z

    您要么需要从 security.yaml 中删除块

    providers:
        in_memory: { memory: null }
    

    或将其更改为类似

    providers:
        app_user_provider:
            entity:
                class: App\Entity\User
                property: email
    

    好吧,在这种情况下,将 provider: app_user_provider 添加到主防火墙

    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            anonymous: lazy
            provider: app_user_provider
            guard:
                authenticators:
                    - App\Security\LoginFormAuthenticator
            logout:
                path: app_logout
    
    • 3

相关问题

Sidebar

Stats

  • 问题 10021
  • Answers 30001
  • 最佳答案 8000
  • 用户 6900
  • 常问
  • 回答
  • Marko Smith

    如何从列表中打印最大元素(str 类型)的长度?

    • 2 个回答
  • Marko Smith

    如何在 PyQT5 中清除 QFrame 的内容

    • 1 个回答
  • Marko Smith

    如何将具有特定字符的字符串拆分为两个不同的列表?

    • 2 个回答
  • Marko Smith

    导航栏活动元素

    • 1 个回答
  • Marko Smith

    是否可以将文本放入数组中?[关闭]

    • 1 个回答
  • Marko Smith

    如何一次用多个分隔符拆分字符串?

    • 1 个回答
  • Marko Smith

    如何通过 ClassPath 创建 InputStream?

    • 2 个回答
  • Marko Smith

    在一个查询中连接多个表

    • 1 个回答
  • Marko Smith

    对列表列表中的所有值求和

    • 3 个回答
  • Marko Smith

    如何对齐 string.Format 中的列?

    • 1 个回答
  • Martin Hope
    Alexandr_TT 2020年新年大赛! 2020-12-20 18:20:21 +0000 UTC
  • Martin Hope
    Alexandr_TT 圣诞树动画 2020-12-23 00:38:08 +0000 UTC
  • Martin Hope
    Air 究竟是什么标识了网站访问者? 2020-11-03 15:49:20 +0000 UTC
  • Martin Hope
    Qwertiy 号码显示 9223372036854775807 2020-07-11 18:16:49 +0000 UTC
  • Martin Hope
    user216109 如何为黑客设下陷阱,或充分击退攻击? 2020-05-10 02:22:52 +0000 UTC
  • Martin Hope
    Qwertiy 并变成3个无穷大 2020-11-06 07:15:57 +0000 UTC
  • Martin Hope
    koks_rs 什么是样板代码? 2020-10-27 15:43:19 +0000 UTC
  • Martin Hope
    Sirop4ik 向 git 提交发布的正确方法是什么? 2020-10-05 00:02:00 +0000 UTC
  • Martin Hope
    faoxis 为什么在这么多示例中函数都称为 foo? 2020-08-15 04:42:49 +0000 UTC
  • Martin Hope
    Pavel Mayorov 如何从事件或回调函数中返回值?或者至少等他们完成。 2020-08-11 16:49:28 +0000 UTC

热门标签

javascript python java php c# c++ html android jquery mysql

Explore

  • 主页
  • 问题
    • 热门问题
    • 最新问题
  • 标签
  • 帮助

Footer

RError.com

关于我们

  • 关于我们
  • 联系我们

Legal Stuff

  • Privacy Policy

帮助

© 2023 RError.com All Rights Reserve   沪ICP备12040472号-5