RError.com

RError.com Logo RError.com Logo

RError.com Navigation

  • 主页

Mobile menu

Close
  • 主页
  • 系统&网络
    • 热门问题
    • 最新问题
    • 标签
  • Ubuntu
    • 热门问题
    • 最新问题
    • 标签
  • 帮助
主页 / user-238886

r.mcreal's questions

Martin Hope
r.mcreal
Asked: 2020-08-28 22:48:08 +0000 UTC

Laravel 在表中创建唯一字段

  • 1

有一个表book_authors链接两个表,books并且authors是多对多关系。该表book_authors具有字段book_id和author_id。您需要创建迁移以更新这些字段并使它们独一无二,即 这样就不会有重复的条目,例如,不应该有:

id  book_id  author_id
1      1          2
2      1          2
         ...

请告诉我,这怎么办?

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-07-09 11:59:00 +0000 UTC

在 docker 中运行 redis

  • 1

有一个用 lumen (laravel) 编写的后端连接到 redis。当我运行本地 php 和本地 redis 时,一切正常。当我通过 docker 运行时,我收到一个错误:Connection refused [tcp://127.0.0.1:6379]. PHP 程序集(Dockerfile):

FROM php:7.2-fpm

RUN apt-get update \
&& chown -R www-data:www-data /var/www/html \
&& chmod -R 777 /var/www/html

RUN pecl install redis && docker-php-ext-enable redis

docker-compose.yml 文件:

  nginx:
    image: nginx:latest
    ports:
    - 127.0.0.1:80:80
    volumes:
    - .:/var/www/html
    - ./docker/config/nginx:/etc/nginx/conf.d
    - ./docker/logs/nginx:/var/log/nginx
    links:
      - php-fpm

  php-fpm:
    build:
      context: ./docker/php-fpm
    volumes:
    - .:/var/www/html

  redis:
    image: redis
    restart: always
    ports:
      - 127.0.0.1:6379:6379
    logging:
      driver: none

可能是什么问题呢?也许我没有打开一些端口?

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-04-06 00:06:22 +0000 UTC

symfony 4 上的 API 身份验证

  • 0

我正在尝试在 symfony 上创建一个 REST API 服务(不使用 api 平台)。达到用户认证。我是否正确理解了算法?

1) Проходим обычную аутентификацию 
2) Создаем apiKey и записываем его в бд
3) Возвращаем клиенту этот apiKey
4) При каждом обращении клиента к серверу проверяем валидность apiKey

?

如果是,如何正确执行?使用什么服务等等。从第一步开始。建议使用最少的第三方服务,但只能使用 symfony 开发人员自己推荐的服务

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-03-21 21:39:27 +0000 UTC

以 json 形式返回错误

  • 0

symfony 4 中有一个注释只允许POST请求,如果没有发送请求,则会POST出现标准的 symfony 错误。我怎样才能捕捉到这个错误,以便我可以将它返回为json?

 `/**
 * @Route("/add_user", name="add_user", methods="POST")
 */`
symfony
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-02-11 14:28:34 +0000 UTC

symfony 授权时出错

  • 1

在命令的帮助下make:auth创建了授权。用用户填满表格。当我尝试登录时,我收到一条错误消息:

There is no user provider for user "App\Entity\User". Shouldn't the "supportsClass()" method of your user provider return true for this classname?

怎么了?似乎我按照文档https://symfony.com/doc/current/security/form_login_setup.html中的指示做了所有事情

我的安全.yaml

    encoders:
        App\Entity\User:
            algorithm: bcrypt
            cost: 12
    # https://symfony.com/doc/current/security.html#where-do-users-come-from-user-providers
    providers:
        in_memory: { memory: null }
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            anonymous: lazy
            guard:
                authenticators:
                    - App\Security\LoginFormAuthenticator
            logout:
                path: app_logout
                # where to redirect after logout
                # target: app_any_route

            # activate different ways to authenticate
            # https://symfony.com/doc/current/security.html#firewalls-authentication

            # https://symfony.com/doc/current/security/impersonating_user.html
            # switch_user: true

    # Easy way to control access for large sections of your site
    # Note: Only the *first* access control that matches will be used
    access_control:
        # - { path: ^/admin, roles: ROLE_ADMIN }
        # - { path: ^/profile, roles: ROLE_USER }

Guard(表单处理)


namespace App\Security;

use App\Entity\User;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Symfony\Component\Security\Core\Exception\CustomUserMessageAuthenticationException;
use Symfony\Component\Security\Core\Exception\InvalidCsrfTokenException;
use Symfony\Component\Security\Core\Security;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Csrf\CsrfToken;
use Symfony\Component\Security\Csrf\CsrfTokenManagerInterface;
use Symfony\Component\Security\Guard\Authenticator\AbstractFormLoginAuthenticator;
use Symfony\Component\Security\Guard\PasswordAuthenticatedInterface;
use Symfony\Component\Security\Http\Util\TargetPathTrait;

class LoginFormAuthenticator extends AbstractFormLoginAuthenticator implements PasswordAuthenticatedInterface
{
    use TargetPathTrait;

    private $entityManager;
    private $urlGenerator;
    private $csrfTokenManager;
    private $passwordEncoder;

    public function __construct(EntityManagerInterface $entityManager, UrlGeneratorInterface $urlGenerator, CsrfTokenManagerInterface $csrfTokenManager, UserPasswordEncoderInterface $passwordEncoder)
    {
        $this->entityManager = $entityManager;
        $this->urlGenerator = $urlGenerator;
        $this->csrfTokenManager = $csrfTokenManager;
        $this->passwordEncoder = $passwordEncoder;
    }

    public function supports(Request $request)
    {
        return 'app_login' === $request->attributes->get('_route')
            && $request->isMethod('POST');
    }

    public function getCredentials(Request $request)
    {
        $credentials = [
            'email' => $request->request->get('email'),
            'password' => $request->request->get('password'),
            'csrf_token' => $request->request->get('_csrf_token'),
        ];
        $request->getSession()->set(
            Security::LAST_USERNAME,
            $credentials['email']
        );

        return $credentials;
    }

    public function getUser($credentials, UserProviderInterface $userProvider)
    {
        $token = new CsrfToken('authenticate', $credentials['csrf_token']);
        if (!$this->csrfTokenManager->isTokenValid($token)) {
            throw new InvalidCsrfTokenException();
        }

        $user = $this->entityManager->getRepository(User::class)->findOneBy(['email' => $credentials['email']]);

        if (!$user) {
            // fail authentication with a custom error
            throw new CustomUserMessageAuthenticationException('Email could not be found.');
        }

        return $user;
    }

    public function checkCredentials($credentials, UserInterface $user)
    {
        return $this->passwordEncoder->isPasswordValid($user, $credentials['password']);
    }

    /**
     * Used to upgrade (rehash) the user's password automatically over time.
     */
    public function getPassword($credentials): ?string
    {
        return $credentials['password'];
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey)
    {
        if ($targetPath = $this->getTargetPath($request->getSession(), $providerKey)) {
            return new RedirectResponse($targetPath);
        }

        // For example : return new RedirectResponse($this->urlGenerator->generate('some_route'));
        //throw new \Exception('TODO: provide a valid redirect inside '.__FILE__);

        return new RedirectResponse($this->urlGenerator->generate('app_homepage'));


    }

    protected function getLoginUrl()
    {
        return $this->urlGenerator->generate('app_login');
    }
}

PS在此之前,我在 UserProvider 中编辑了supportsClass,使其不返回false:

{
    return $class === UserIdentity::class;
}
php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-09-15 23:42:00 +0000 UTC

在选择时提交表格

  • 0

有这样的html

<form action="/config/lang" method="POST" >
    <select class="select_send_ajax selectpicker">
       <option>1</option>
       <option>2</option>                 
    </select>
 </form>

还有负责处理的js

$('.select_send_ajax').on('change', function () {
    this.form.submit();
});


$('form').submit(function(event) { //Отправка всех форм        
      console.log(123);
      event.preventDefault();
}

当我选择某些内容时,select会立即发送表单,尽管我们已禁用表单提交。有必要选择时,select表单会尝试走,但由于我们禁止它,它只会显示123在控制台中

javascript
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-04-02 17:15:50 +0000 UTC

按类别 id 获取所有产品

  • 0

你好!有一个对返回所有产品的数据库的查询:

SELECT SQL_CALC_FOUND_ROWS 
       p.product_id as 'product_id', 
       p.image as 'p.image', 
       p.price as 'p.price', 
       pd.name as 'pd.name', 
       ms.seller_id as 'seller_id', 
       ms.nickname as 'ms.nickname', 
       mp.product_status as 'mp.product_status', 
       mp.product_approved as 'mp.product_approved', 
       mp.number_sold as 'mp.number_sold', 
       mp.list_until as 'mp.list_until', 
       p.date_added as 'p.date_created', 
       p.date_modified as 'p.date_modified', 
       pd.description as 'pd.description' 
FROM oc_product p 
INNER JOIN oc_product_description pd USING(product_id)
LEFT JOIN oc_ms_product mp USING(product_id)
LEFT JOIN oc_ms_seller ms USING (seller_id) 
WHERE 1 = 1 AND ms.seller_id = 27 AND product_status IN (1) 
GROUP BY p.product_id 
HAVING 1 = 1 
ORDER BY pd.name ASC LIMIT 0, 12

例如,您需要参考该表oc_product_to_category(其中包含字段product_id和category_id)并仅使用 =1 的那些产品category_id。我不知道该怎么做

mysql
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-03-28 18:17:36 +0000 UTC

简单的mysql查询

  • 0

你好!有要求

SELECT * FROM `product` LEFT JOIN `category_product` ON (product.category = category_product.id) WHERE (category_product.seo_url = 'category1')`

两个表都包含name和seo_url。问题是,我怎样才能明确指定应该从服务器上已经存在name的表中获取什么?PS我尝试使用它但它不起作用(seo_urlproductas

mysql
  • 2 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-02-22 22:33:16 +0000 UTC

按价值对产品进行排序

  • 0

你好!有一个显示所有产品的查询:

SELECT p.product_id, 
 (SELECT AVG(rating) AS total 
  FROM oc_review r1 
  WHERE r1.product_id = p.product_id AND r1.status = '1' 
  GROUP BY r1.product_id) AS rating, 
 (SELECT price 
  FROM oc_product_discount pd2 
  WHERE pd2.product_id = p.product_id 
    AND pd2.customer_group_id = '1' 
    AND pd2.quantity = '1' 
    AND ((pd2.date_start = '0000-00-00' OR pd2.date_start < NOW()) 
    AND (pd2.date_end = '0000-00-00' OR pd2.date_end > NOW())) 
  ORDER BY pd2.priority ASC, pd2.price ASC LIMIT 1) AS discount, 
 (SELECT price 
  FROM oc_product_special ps 
  WHERE ps.product_id = p.product_id 
    AND ps.customer_group_id = '1' 
    AND ((ps.date_start = '0000-00-00' OR ps.date_start < NOW()) 
    AND (ps.date_end = '0000-00-00' OR ps.date_end > NOW())) 
  ORDER BY ps.priority ASC, ps.price ASC LIMIT 1) AS special 
FROM oc_product_to_category p2c 
LEFT JOIN oc_product p ON (p2c.product_id = p.product_id) 
LEFT JOIN oc_product_description pd ON (p.product_id = pd.product_id) 
LEFT JOIN oc_product_to_store p2s ON (p.product_id = p2s.product_id) 
  WHERE pd.language_id = '1' 
    AND p.status = '1' 
    AND p.date_available <= NOW() 
    AND p2s.store_id = '0' 
    AND p2c.category_id = '76' 
GROUP BY p.product_id 
ORDER BY rating ASC, LCASE(pd.name) ASC 
LIMIT 0,15

我需要先显示所有具有 的产品,position=1然后再显示所有其他产品。我试图在最后添加ORDER BY position='1' DESC,给出了一个错误。PS 请告诉我,我在哪里犯了错误(在 mysql 中,不幸的是,我理解马马虎虎)

mysql
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-20 18:33:09 +0000 UTC

获取类别 URL

  • 1

你好!我想知道帖子类别 ID。知道帖子的id,怎么办?PS 自定义类别,分类ad_cat。

wordpress
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-20 13:56:25 +0000 UTC

显示某个类别的帖子

  • 0

你好!我只想在网站上显示某个类别的帖子(使用类别 ID)。有这个代码:

$args = array(
 'numberposts' => '100000',
 'category' => 35,
 'post_type' => 'ad_listing',
);

$posts = get_posts($args);

但由于某种原因,数组是$posts空的。如果删除'category' => 35它,它会正常显示所有帖子

wordpress
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-19 20:55:41 +0000 UTC

选择元素时获取值

  • 0

你好!该网站有一个下拉列表:

<ul class="dropdown-menu">
                    <li>Один</li>
                    <li>Два</li>
                    <li>Три</li>
</ul>

li选择任何值(即在操作期间)时,如何使用 jquery 获取值(例如 data-... change)?

jquery
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-15 21:26:47 +0000 UTC

剪切子串

  • 0

你好!有这样的行:

/city/ufa/val1/

/city/kazan/val2/val3/

有必要从字符串中取出最后一个单词,即 从倒数第二个/到最后一个/(例如:第一种情况是 'val1',第二种情况是 'val3')。如何实施?

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-14 16:07:54 +0000 UTC

用户余额减法问题

  • 1

你好!该网站有一个代码,用于从该用户的每个帖子的用户余额中删除单位(提取多少取决于帖子本身的速率):

foreach ($posts as $post) {
 if (is_sticky($post->ID) == true) 
    {
        $postAutorId = $post->post_author;   
        $postAutorId = $postAutorId[0]; //id автора поста

        $rate = get_post_meta($post->ID, 'cp_sys_total_ad_cost');
        $rate = intval($rate[0]); // ставка за данный пост

        $balance = get_user_meta($postAutorId, 'balance');
        $balance = intval($balance[0]); //баланс пользователя

        if($balance == '')
        {
            $balance = 0;
        }

        if($balance >= $rate) //Если баланс больше или равно ставке, уменьшаем баланс на ставку
        {
            $balance = $balance - $rate;

            $res = $wpdb->query(
                    " UPDATE `wp_usermeta` SET `meta_value` = '$balance' WHERE `meta_key`='billing_city' AND `wp_usermeta`.`user_id` = '$postAutorId';"
            ); //Перезаписываем баланс

            echo '<pre>';
                var_dump($balance);
            echo '<pre>';    
        }

        else
        {
            //закрываем пост
            // $wpdb->query(
               //     "UPDATE `wp_posts` SET `post_status` = 'pending' WHERE `wp_posts`.`ID` = '$postAutorId';"
            // );
        }       
    }
}

问题是,如果一个作者有两个帖子,由于某种原因,只扣除最后一个帖子的余额(例如:余额是'100',第一个帖子是'50',第二个帖子是'45'。如结果,用户的余额将是“55”而不是“5”)

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-12 17:54:13 +0000 UTC

按键排序二维数组

  • 0

你好!我有一个二维数组:

array(7) {
 [0]=>
  array(4) {
  [0]=>
  int(529)
  [1]=>
  string(5) "40.00"
         }
 [1]=>
   array(4) {
   [0]=>
   int(525)
   [1]=>
   string(5) "50.00"

   ...
}

[1]有必要按键(即按元素 40.00、50.00)以相反的顺序对该数组进行排序。如何实施?

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-12-11 18:10:02 +0000 UTC

WordPress 看不到标准功能

  • 0

我在主题的根目录中创建了一个包含 php 文件的文件夹。当我尝试在这些文件中运行标准函数时(例如:)update_post_meta,它返回 500 错误,并写入日志Call to undefined function update_post_meta() in ...。也许您需要在某处包含您的 php 文件,以便您可以在其中调用标准 WP 函数?

wordpress
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-11-22 18:10:59 +0000 UTC

WordPress 发布订单

  • 0

你好!WP 在哪里以及如何组成所有帖子的数组(对数据库的查询在哪里)?这是显示所有帖子的代码:

<?php while (have_posts()) : the_post(); ?>

    <?php appthemes_before_post(); ?>

    <?php get_template_part('content', APP_POST_TYPE); ?>

    <?php appthemes_after_post(); ?>

<?php endwhile; ?>

<?php appthemes_after_endwhile(); ?>

 <?php else: ?>

   <?php appthemes_loop_else(); ?>

<?php endif; ?>

我需要重做数据库查询以更改帖子输出的顺序

php
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-10-31 17:26:38 +0000 UTC

JS - 从选择中获取价值

  • 0

网站上有几个select循环显示:

$(".selectOptions").change(function() {
  var href = $(".selectOptions :selected").val();
  console.log(href);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select size="6" class="color form-control ocf-target selected selectOptions" name="color">

       <option class="ir_Все" value="http://.../index.php?route=product/category&amp;path=59" id="v-cancel-1">Все</option>
       <option class="ir_3597ae" value="" id="v-12" disabled="disabled">Синий</option>
       <option class="ir_ffffff" value="http://.../index.php?route=product/category&amp;path=59&amp;filter_ocfilter=1:22" id="v-122">Белый</option>
                                                                                                        
    </select>


<select size="6" class="color form-control ocf-target selected selectOptions" name="color">

       <option class="ir_fbaf00" value="http://.../index.php?route=product/category&amp;path=59&amp;filter_ocfilter=1:3" id="v-13" selected="selected">Желтый</option>
       <option class="ir_ff0000" value="" id="v-11" disabled="disabled">Красный</option>
                                                                                                        
    </select> ...

选择字段时,需要获取该字段的值。但由于某种原因,它仅从 first 中获取值select。

javascript
  • 1 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-10-26 17:25:18 +0000 UTC

展开选择

  • 1

你好!该站点有几个使用循环显示的选择。每个选择都应在单击特定按钮时展开(使用 js 和 css)。到目前为止,只有打开所有选择,但不是单独打开。那些。最后应该是这样的,点击Цвет一个所有颜色都掉的列表,其余的列表不显示。PS循环中的选择数量可以改变,即 并不总是等于三

$('body').on('click', '.bnt', function(event) {
  event.preventDefault();
  $('.dropdown').toggle();
})

$('body').on('click', '.dropdown', function(event) {
  event.preventDefault();
  $('.dropdown').toggle();
})
select {
  overflow: hidden;
  border: none;
  text-transform: uppercase;
}

option {
  line-height: 20px;
  padding: .5rem 1rem;
  position: relative;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>


<div class="bnt">ЦВЕТ</div>
<div class="dropdown" style="display: none">
  <select size="3" class="color" name="color">
  <option value="grey" class="grey">белый</option>
  <option value="yellow" class="yellow">желтый</option>
  <option value="green" class="green">зеленый</option>
</select>
</div>


<div class="bnt">Форма</div>
<div class="dropdown" style="display: none">
  <select size="3" class="color" name="color">
  <option value="grey" class="grey">Шар</option>
  <option value="yellow" class="yellow">Куб</option>
  <option value="green" class="green">Конус</option>
</select>


</div>



<div class="bnt">Содержимое</div>
<div class="dropdown" style="display: none">
  <select size="3" class="color" name="color">
  <option value="grey" class="grey">Текст1</option>
  <option value="yellow" class="yellow">Текст2</option>
  <option value="green" class="green">Текст3</option>
</select>


</div>

javascript
  • 2 个回答
  • 10 Views
Martin Hope
r.mcreal
Asked: 2020-10-26 03:03:48 +0000 UTC

从 <select> 到下拉菜单

  • 1

你好!在网站上,<select>需要在引导下重新制作它dropdown(不要问为什么))。那些。以便列表最初不可见,但仅在按下按钮后才可见。这是应该发生的事情的示例:在此处输入图像描述

那些。有一个按钮可以打开列表和列表本身。当您从列表中选择任何元素时,会发生 js 事件,因此您需要使用<select>

javascript
  • 1 个回答
  • 10 Views

Sidebar

Stats

  • 问题 10021
  • Answers 30001
  • 最佳答案 8000
  • 用户 6900
  • 常问
  • 回答
  • Marko Smith

    我看不懂措辞

    • 1 个回答
  • Marko Smith

    请求的模块“del”不提供名为“default”的导出

    • 3 个回答
  • Marko Smith

    "!+tab" 在 HTML 的 vs 代码中不起作用

    • 5 个回答
  • Marko Smith

    我正在尝试解决“猜词”的问题。Python

    • 2 个回答
  • Marko Smith

    可以使用哪些命令将当前指针移动到指定的提交而不更改工作目录中的文件?

    • 1 个回答
  • Marko Smith

    Python解析野莓

    • 1 个回答
  • Marko Smith

    问题:“警告:检查最新版本的 pip 时出错。”

    • 2 个回答
  • Marko Smith

    帮助编写一个用值填充变量的循环。解决这个问题

    • 2 个回答
  • Marko Smith

    尽管依赖数组为空,但在渲染上调用了 2 次 useEffect

    • 2 个回答
  • Marko Smith

    数据不通过 Telegram.WebApp.sendData 发送

    • 1 个回答
  • Martin Hope
    Alexandr_TT 2020年新年大赛! 2020-12-20 18:20:21 +0000 UTC
  • Martin Hope
    Alexandr_TT 圣诞树动画 2020-12-23 00:38:08 +0000 UTC
  • Martin Hope
    Air 究竟是什么标识了网站访问者? 2020-11-03 15:49:20 +0000 UTC
  • Martin Hope
    Qwertiy 号码显示 9223372036854775807 2020-07-11 18:16:49 +0000 UTC
  • Martin Hope
    user216109 如何为黑客设下陷阱,或充分击退攻击? 2020-05-10 02:22:52 +0000 UTC
  • Martin Hope
    Qwertiy 并变成3个无穷大 2020-11-06 07:15:57 +0000 UTC
  • Martin Hope
    koks_rs 什么是样板代码? 2020-10-27 15:43:19 +0000 UTC
  • Martin Hope
    Sirop4ik 向 git 提交发布的正确方法是什么? 2020-10-05 00:02:00 +0000 UTC
  • Martin Hope
    faoxis 为什么在这么多示例中函数都称为 foo? 2020-08-15 04:42:49 +0000 UTC
  • Martin Hope
    Pavel Mayorov 如何从事件或回调函数中返回值?或者至少等他们完成。 2020-08-11 16:49:28 +0000 UTC

热门标签

javascript python java php c# c++ html android jquery mysql

Explore

  • 主页
  • 问题
    • 热门问题
    • 最新问题
  • 标签
  • 帮助

Footer

RError.com

关于我们

  • 关于我们
  • 联系我们

Legal Stuff

  • Privacy Policy

帮助

© 2023 RError.com All Rights Reserve   沪ICP备12040472号-5