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r.mcreal's questions

Martin Hope
r.mcreal
Asked: 2020-08-28 22:48:08 +0800 CST
  • 1

有一个表book_authors链接两个表，books并且authors是多对多关系。该表book_authors具有字段book_id和author_id。您需要创建迁移以更新这些字段并使它们独一无二，即 这样就不会有重复的条目，例如，不应该有：

id  book_id  author_id
1      1          2
2      1          2
         ...

请告诉我，这怎么办？

php
Martin Hope
r.mcreal
Asked: 2020-07-09 11:59:00 +0800 CST
  • 1

有一个用 lumen (laravel) 编写的后端连接到 redis。当我运行本地 php 和本地 redis 时，一切正常。当我通过 docker 运行时，我收到一个错误：Connection refused [tcp://127.0.0.1:6379]. PHP 程序集（Dockerfile）：

FROM php:7.2-fpm

RUN apt-get update \
&& chown -R www-data:www-data /var/www/html \
&& chmod -R 777 /var/www/html

RUN pecl install redis && docker-php-ext-enable redis

docker-compose.yml 文件：

  nginx:
    image: nginx:latest
    ports:
    - 127.0.0.1:80:80
    volumes:
    - .:/var/www/html
    - ./docker/config/nginx:/etc/nginx/conf.d
    - ./docker/logs/nginx:/var/log/nginx
    links:
      - php-fpm

  php-fpm:
    build:
      context: ./docker/php-fpm
    volumes:
    - .:/var/www/html

  redis:
    image: redis
    restart: always
    ports:
      - 127.0.0.1:6379:6379
    logging:
      driver: none

可能是什么问题呢？也许我没有打开一些端口？

php
Martin Hope
r.mcreal
Asked: 2020-04-06 00:06:22 +0800 CST
  • 0

我正在尝试在 symfony 上创建一个 REST API 服务（不使用 api 平台）。达到用户认证。我是否正确理解了算法？

1) Проходим обычную аутентификацию 
2) Создаем apiKey и записываем его в бд
3) Возвращаем клиенту этот apiKey
4) При каждом обращении клиента к серверу проверяем валидность apiKey

?

如果是，如何正确执行？使用什么服务等等。从第一步开始。建议使用最少的第三方服务，但只能使用 symfony 开发人员自己推荐的服务

php
Martin Hope
r.mcreal
Asked: 2020-02-11 14:28:34 +0800 CST
  • 1

在命令的帮助下make:auth创建了授权。用用户填满表格。当我尝试登录时，我收到一条错误消息：

There is no user provider for user "App\Entity\User". Shouldn't the "supportsClass()" method of your user provider return true for this classname?

怎么了？似乎我按照文档https://symfony.com/doc/current/security/form_login_setup.html中的指示做了所有事情

我的安全.yaml

    encoders:
        App\Entity\User:
            algorithm: bcrypt
            cost: 12
    # https://symfony.com/doc/current/security.html#where-do-users-come-from-user-providers
    providers:
        in_memory: { memory: null }
    firewalls:
        dev:
            pattern: ^/(_(profiler|wdt)|css|images|js)/
            security: false
        main:
            anonymous: lazy
            guard:
                authenticators:
                    - App\Security\LoginFormAuthenticator
            logout:
                path: app_logout
                # where to redirect after logout
                # target: app_any_route

            # activate different ways to authenticate
            # https://symfony.com/doc/current/security.html#firewalls-authentication

            # https://symfony.com/doc/current/security/impersonating_user.html
            # switch_user: true

    # Easy way to control access for large sections of your site
    # Note: Only the *first* access control that matches will be used
    access_control:
        # - { path: ^/admin, roles: ROLE_ADMIN }
        # - { path: ^/profile, roles: ROLE_USER }

Guard（表单处理）


namespace App\Security;

use App\Entity\User;
use Doctrine\ORM\EntityManagerInterface;
use Symfony\Component\HttpFoundation\RedirectResponse;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Generator\UrlGeneratorInterface;
use Symfony\Component\Security\Core\Authentication\Token\TokenInterface;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Symfony\Component\Security\Core\Exception\CustomUserMessageAuthenticationException;
use Symfony\Component\Security\Core\Exception\InvalidCsrfTokenException;
use Symfony\Component\Security\Core\Security;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\User\UserProviderInterface;
use Symfony\Component\Security\Csrf\CsrfToken;
use Symfony\Component\Security\Csrf\CsrfTokenManagerInterface;
use Symfony\Component\Security\Guard\Authenticator\AbstractFormLoginAuthenticator;
use Symfony\Component\Security\Guard\PasswordAuthenticatedInterface;
use Symfony\Component\Security\Http\Util\TargetPathTrait;

class LoginFormAuthenticator extends AbstractFormLoginAuthenticator implements PasswordAuthenticatedInterface
{
    use TargetPathTrait;

    private $entityManager;
    private $urlGenerator;
    private $csrfTokenManager;
    private $passwordEncoder;

    public function __construct(EntityManagerInterface $entityManager, UrlGeneratorInterface $urlGenerator, CsrfTokenManagerInterface $csrfTokenManager, UserPasswordEncoderInterface $passwordEncoder)
    {
        $this->entityManager = $entityManager;
        $this->urlGenerator = $urlGenerator;
        $this->csrfTokenManager = $csrfTokenManager;
        $this->passwordEncoder = $passwordEncoder;
    }

    public function supports(Request $request)
    {
        return 'app_login' === $request->attributes->get('_route')
            && $request->isMethod('POST');
    }

    public function getCredentials(Request $request)
    {
        $credentials = [
            'email' => $request->request->get('email'),
            'password' => $request->request->get('password'),
            'csrf_token' => $request->request->get('_csrf_token'),
        ];
        $request->getSession()->set(
            Security::LAST_USERNAME,
            $credentials['email']
        );

        return $credentials;
    }

    public function getUser($credentials, UserProviderInterface $userProvider)
    {
        $token = new CsrfToken('authenticate', $credentials['csrf_token']);
        if (!$this->csrfTokenManager->isTokenValid($token)) {
            throw new InvalidCsrfTokenException();
        }

        $user = $this->entityManager->getRepository(User::class)->findOneBy(['email' => $credentials['email']]);

        if (!$user) {
            // fail authentication with a custom error
            throw new CustomUserMessageAuthenticationException('Email could not be found.');
        }

        return $user;
    }

    public function checkCredentials($credentials, UserInterface $user)
    {
        return $this->passwordEncoder->isPasswordValid($user, $credentials['password']);
    }

    /**
     * Used to upgrade (rehash) the user's password automatically over time.
     */
    public function getPassword($credentials): ?string
    {
        return $credentials['password'];
    }

    public function onAuthenticationSuccess(Request $request, TokenInterface $token, $providerKey)
    {
        if ($targetPath = $this->getTargetPath($request->getSession(), $providerKey)) {
            return new RedirectResponse($targetPath);
        }

        // For example : return new RedirectResponse($this->urlGenerator->generate('some_route'));
        //throw new \Exception('TODO: provide a valid redirect inside '.__FILE__);

        return new RedirectResponse($this->urlGenerator->generate('app_homepage'));


    }

    protected function getLoginUrl()
    {
        return $this->urlGenerator->generate('app_login');
    }
}

PS在此之前，我在 UserProvider 中编辑了supportsClass，使其不返回false：

{
    return $class === UserIdentity::class;
}
php
Martin Hope
r.mcreal
Asked: 2020-09-15 23:42:00 +0800 CST
  • 0

有这样的html

<form action="/config/lang" method="POST" >
    <select class="select_send_ajax selectpicker">
       <option>1</option>
       <option>2</option>                 
    </select>
 </form>

还有负责处理的js

$('.select_send_ajax').on('change', function () {
    this.form.submit();
});


$('form').submit(function(event) { //Отправка всех форм        
      console.log(123);
      event.preventDefault();
}

当我选择某些内容时，select会立即发送表单，尽管我们已禁用表单提交。有必要选择时，select表单会尝试走，但由于我们禁止它，它只会显示123在控制台中

javascript
Martin Hope
r.mcreal
Asked: 2020-04-02 17:15:50 +0800 CST
  • 0

你好！有一个对返回所有产品的数据库的查询：

SELECT SQL_CALC_FOUND_ROWS 
       p.product_id as 'product_id', 
       p.image as 'p.image', 
       p.price as 'p.price', 
       pd.name as 'pd.name', 
       ms.seller_id as 'seller_id', 
       ms.nickname as 'ms.nickname', 
       mp.product_status as 'mp.product_status', 
       mp.product_approved as 'mp.product_approved', 
       mp.number_sold as 'mp.number_sold', 
       mp.list_until as 'mp.list_until', 
       p.date_added as 'p.date_created', 
       p.date_modified as 'p.date_modified', 
       pd.description as 'pd.description' 
FROM oc_product p 
INNER JOIN oc_product_description pd USING(product_id)
LEFT JOIN oc_ms_product mp USING(product_id)
LEFT JOIN oc_ms_seller ms USING (seller_id) 
WHERE 1 = 1 AND ms.seller_id = 27 AND product_status IN (1) 
GROUP BY p.product_id 
HAVING 1 = 1 
ORDER BY pd.name ASC LIMIT 0, 12

例如，您需要参考该表oc_product_to_category（其中包含字段product_id和category_id）并仅使用 =1 的那些产品category_id。我不知道该怎么做

mysql
Martin Hope
r.mcreal
Asked: 2020-03-28 18:17:36 +0800 CST
  • 0

你好！有要求

SELECT * FROM `product` LEFT JOIN `category_product` ON (product.category = category_product.id) WHERE (category_product.seo_url = 'category1')`

两个表都包含name和seo_url。问题是，我怎样才能明确指定应该从服务器上已经存在name的表中获取什么？PS我尝试使用它但它不起作用（seo_urlproductas

mysql
Martin Hope
r.mcreal
Asked: 2020-02-22 22:33:16 +0800 CST
  • 0

你好！有一个显示所有产品的查询：

SELECT p.product_id, 
 (SELECT AVG(rating) AS total 
  FROM oc_review r1 
  WHERE r1.product_id = p.product_id AND r1.status = '1' 
  GROUP BY r1.product_id) AS rating, 
 (SELECT price 
  FROM oc_product_discount pd2 
  WHERE pd2.product_id = p.product_id 
    AND pd2.customer_group_id = '1' 
    AND pd2.quantity = '1' 
    AND ((pd2.date_start = '0000-00-00' OR pd2.date_start < NOW()) 
    AND (pd2.date_end = '0000-00-00' OR pd2.date_end > NOW())) 
  ORDER BY pd2.priority ASC, pd2.price ASC LIMIT 1) AS discount, 
 (SELECT price 
  FROM oc_product_special ps 
  WHERE ps.product_id = p.product_id 
    AND ps.customer_group_id = '1' 
    AND ((ps.date_start = '0000-00-00' OR ps.date_start < NOW()) 
    AND (ps.date_end = '0000-00-00' OR ps.date_end > NOW())) 
  ORDER BY ps.priority ASC, ps.price ASC LIMIT 1) AS special 
FROM oc_product_to_category p2c 
LEFT JOIN oc_product p ON (p2c.product_id = p.product_id) 
LEFT JOIN oc_product_description pd ON (p.product_id = pd.product_id) 
LEFT JOIN oc_product_to_store p2s ON (p.product_id = p2s.product_id) 
  WHERE pd.language_id = '1' 
    AND p.status = '1' 
    AND p.date_available <= NOW() 
    AND p2s.store_id = '0' 
    AND p2c.category_id = '76' 
GROUP BY p.product_id 
ORDER BY rating ASC, LCASE(pd.name) ASC 
LIMIT 0,15

我需要先显示所有具有 的产品，position=1然后再显示所有其他产品。我试图在最后添加ORDER BY position='1' DESC，给出了一个错误。PS 请告诉我，我在哪里犯了错误（在 mysql 中，不幸的是，我理解马马虎虎）

mysql
Martin Hope
r.mcreal
Asked: 2020-12-20 13:56:25 +0800 CST
  • 0

你好！我只想在网站上显示某个类别的帖子（使用类别 ID）。有这个代码：

$args = array(
 'numberposts' => '100000',
 'category' => 35,
 'post_type' => 'ad_listing',
);

$posts = get_posts($args);

但由于某种原因，数组是$posts空的。如果删除'category' => 35它，它会正常显示所有帖子

wordpress
Martin Hope
r.mcreal
Asked: 2020-12-15 21:26:47 +0800 CST
  • 0

你好！有这样的行：

/city/ufa/val1/

/city/kazan/val2/val3/

有必要从字符串中取出最后一个单词，即 从倒数第二个/到最后一个/（例如：第一种情况是 'val1'，第二种情况是 'val3'）。如何实施？

php
Martin Hope
r.mcreal
Asked: 2020-12-14 16:07:54 +0800 CST
  • 1

你好！该网站有一个代码，用于从该用户的每个帖子的用户余额中删除单位（提取多少取决于帖子本身的速率）：

foreach ($posts as $post) {
 if (is_sticky($post->ID) == true) 
    {
        $postAutorId = $post->post_author;   
        $postAutorId = $postAutorId[0]; //id автора поста

        $rate = get_post_meta($post->ID, 'cp_sys_total_ad_cost');
        $rate = intval($rate[0]); // ставка за данный пост

        $balance = get_user_meta($postAutorId, 'balance');
        $balance = intval($balance[0]); //баланс пользователя

        if($balance == '')
        {
            $balance = 0;
        }

        if($balance >= $rate) //Если баланс больше или равно ставке, уменьшаем баланс на ставку
        {
            $balance = $balance - $rate;

            $res = $wpdb->query(
                    " UPDATE `wp_usermeta` SET `meta_value` = '$balance' WHERE `meta_key`='billing_city' AND `wp_usermeta`.`user_id` = '$postAutorId';"
            ); //Перезаписываем баланс

            echo '<pre>';
                var_dump($balance);
            echo '<pre>';    
        }

        else
        {
            //закрываем пост
            // $wpdb->query(
               //     "UPDATE `wp_posts` SET `post_status` = 'pending' WHERE `wp_posts`.`ID` = '$postAutorId';"
            // );
        }       
    }
}

问题是，如果一个作者有两个帖子，由于某种原因，只扣除最后一个帖子的余额（例如：余额是'100'，第一个帖子是'50'，第二个帖子是'45'。如结果，用户的余额将是“55”而不是“5”）

php
Martin Hope
r.mcreal
Asked: 2020-12-11 18:10:02 +0800 CST
  • 0

我在主题的根目录中创建了一个包含 php 文件的文件夹。当我尝试在这些文件中运行标准函数时（例如：）update_post_meta，它返回 500 错误，并写入日志Call to undefined function update_post_meta() in ...。也许您需要在某处包含您的 php 文件，以便您可以在其中调用标准 WP 函数？

wordpress
Martin Hope
r.mcreal
Asked: 2020-11-22 18:10:59 +0800 CST
  • 0

你好！WP 在哪里以及如何组成所有帖子的数组（对数据库的查询在哪里）？这是显示所有帖子的代码：

<?php while (have_posts()) : the_post(); ?>

    <?php appthemes_before_post(); ?>

    <?php get_template_part('content', APP_POST_TYPE); ?>

    <?php appthemes_after_post(); ?>

<?php endwhile; ?>

<?php appthemes_after_endwhile(); ?>

 <?php else: ?>

   <?php appthemes_loop_else(); ?>

<?php endif; ?>

我需要重做数据库查询以更改帖子输出的顺序

php
Martin Hope
r.mcreal
Asked: 2020-10-31 17:26:38 +0800 CST
  • 0

网站上有几个select循环显示：

$(".selectOptions").change(function() {
  var href = $(".selectOptions :selected").val();
  console.log(href);
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<select size="6" class="color form-control ocf-target selected selectOptions" name="color">

       <option class="ir_Все" value="http://.../index.php?route=product/category&amp;path=59" id="v-cancel-1">Все</option>
       <option class="ir_3597ae" value="" id="v-12" disabled="disabled">Синий</option>
       <option class="ir_ffffff" value="http://.../index.php?route=product/category&amp;path=59&amp;filter_ocfilter=1:22" id="v-122">Белый</option>
                                                                                                        
    </select>


<select size="6" class="color form-control ocf-target selected selectOptions" name="color">

       <option class="ir_fbaf00" value="http://.../index.php?route=product/category&amp;path=59&amp;filter_ocfilter=1:3" id="v-13" selected="selected">Желтый</option>
       <option class="ir_ff0000" value="" id="v-11" disabled="disabled">Красный</option>
                                                                                                        
    </select> ...

选择字段时，需要获取该字段的值。但由于某种原因，它仅从 first 中获取值select。

javascript
Martin Hope
r.mcreal
Asked: 2020-10-26 17:25:18 +0800 CST
  • 1

你好！该站点有几个使用循环显示的选择。每个选择都应在单击特定按钮时展开（使用 js 和 css）。到目前为止，只有打开所有选择，但不是单独打开。那些。最后应该是这样的，点击Цвет一个所有颜色都掉的列表，其余的列表不显示。PS循环中的选择数量可以改变，即 并不总是等于三

$('body').on('click', '.bnt', function(event) {
  event.preventDefault();
  $('.dropdown').toggle();
})

$('body').on('click', '.dropdown', function(event) {
  event.preventDefault();
  $('.dropdown').toggle();
})
select {
  overflow: hidden;
  border: none;
  text-transform: uppercase;
}

option {
  line-height: 20px;
  padding: .5rem 1rem;
  position: relative;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.0/jquery.min.js"></script>


<div class="bnt">ЦВЕТ</div>
<div class="dropdown" style="display: none">
  <select size="3" class="color" name="color">
  <option value="grey" class="grey">белый</option>
  <option value="yellow" class="yellow">желтый</option>
  <option value="green" class="green">зеленый</option>
</select>
</div>


<div class="bnt">Форма</div>
<div class="dropdown" style="display: none">
  <select size="3" class="color" name="color">
  <option value="grey" class="grey">Шар</option>
  <option value="yellow" class="yellow">Куб</option>
  <option value="green" class="green">Конус</option>
</select>


</div>



<div class="bnt">Содержимое</div>
<div class="dropdown" style="display: none">
  <select size="3" class="color" name="color">
  <option value="grey" class="grey">Текст1</option>
  <option value="yellow" class="yellow">Текст2</option>
  <option value="green" class="green">Текст3</option>
</select>


</div>

javascript
Martin Hope
r.mcreal
Asked: 2020-10-26 03:03:48 +0800 CST
  • 1

你好！在网站上，<select>需要在引导下重新制作它dropdown（不要问为什么））。那些。以便列表最初不可见，但仅在按下按钮后才可见。这是应该发生的事情的示例：在此处输入图像描述

那些。有一个按钮可以打开列表和列表本身。当您从列表中选择任何元素时，会发生 js 事件，因此您需要使用<select>

javascript