主页 / 问题 / 1089095
Accepted
user3178479
Asked:2020-03-01 02:25:04 +0000 UTC2020-03-01 02:25:04 +0000 UTC

单击内部链接关闭引导下拉菜单

  • 772

在 bootsrap 下拉菜单中创建“后退”链接的选项有哪些？

$('.dropdown-menu .dropdown-toggle').on('click', function(e){
  e.preventDefault();

  $(this).dropdown('toggle');

});
<link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min.css" integrity="sha384-Vkoo8x4CGsO3+Hhxv8T/Q5PaXtkKtu6ug5TOeNV6gBiFeWPGFN9MuhOf23Q9Ifjh" crossorigin="anonymous">
  <script src="https://code.jquery.com/jquery-3.4.1.slim.min.js" integrity="sha384-J6qa4849blE2+poT4WnyKhv5vZF5SrPo0iEjwBvKU7imGFAV0wwj1yYfoRSJoZ+n" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js" integrity="sha384-Q6E9RHvbIyZFJoft+2mJbHaEWldlvI9IOYy5n3zV9zzTtmI3UksdQRVvoxMfooAo" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/js/bootstrap.min.js" integrity="sha384-wfSDF2E50Y2D1uUdj0O3uMBJnjuUD4Ih7YwaYd1iqfktj0Uod8GCExl3Og8ifwB6" crossorigin="anonymous"></script>
  
  <div class="dropdown">
  <a class="btn btn-secondary dropdown-toggle" href="#" role="button" id="dropdownMenuLink" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
    Dropdown link
  </a>

  <div class="dropdown-menu" aria-labelledby="dropdownMenuLink">
    <a class="dropdown-item dropdown-toggle" href="#"> <<< - Back</a>
    <a class="dropdown-item" href="#">Another action</a>
    <a class="dropdown-item" href="#">Something else here</a>
  </div>
</div>

我在努力dropdown('toggle')。

现在它给出了一个错误：

“TypeError：无法在 Object.onLoad 读取属性‘setAttribute’的 null ( https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js:4:20970 )在https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js:4:14236 在 Array.forEach() ....

jquery

2 个回答

  1. Dropdown在您的情况下，当您单击其中的任何链接时，该菜单已经关闭。
    如果您想在单击链接时直接关闭菜单，只需删除showy类即可dropdown。

    $('.dropdown-item .dropdown-toggle').on('click', function(e){
    e.preventDefault();
    $(this).classList.remove('show');
});
    <link rel="stylesheet" href="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/css/bootstrap.min.css" integrity="sha384-Vkoo8x4CGsO3+Hhxv8T/Q5PaXtkKtu6ug5TOeNV6gBiFeWPGFN9MuhOf23Q9Ifjh" crossorigin="anonymous">
<script src="https://code.jquery.com/jquery-3.4.1.slim.min.js" integrity="sha384-J6qa4849blE2+poT4WnyKhv5vZF5SrPo0iEjwBvKU7imGFAV0wwj1yYfoRSJoZ+n" crossorigin="anonymous"></script>
<script src="https://cdn.jsdelivr.net/npm/popper.js@1.16.0/dist/umd/popper.min.js" integrity="sha384-Q6E9RHvbIyZFJoft+2mJbHaEWldlvI9IOYy5n3zV9zzTtmI3UksdQRVvoxMfooAo" crossorigin="anonymous"></script>
<script src="https://stackpath.bootstrapcdn.com/bootstrap/4.4.1/js/bootstrap.min.js" integrity="sha384-wfSDF2E50Y2D1uUdj0O3uMBJnjuUD4Ih7YwaYd1iqfktj0Uod8GCExl3Og8ifwB6" crossorigin="anonymous"></script>


<div class="dropdown">
    <a class="btn btn-secondary dropdown-toggle" href="#" role="button" id="dropdownMenuLink" data-toggle="dropdown" aria-haspopup="true" aria-expanded="false">
        Dropdown link
    </a>

    <div class="dropdown-menu" aria-labelledby="dropdownMenuLink">
        <a class="dropdown-item dropdown-toggle" href="#"> <<< - Back</a>
        <a class="dropdown-item" href="#">Another action</a>
        <a class="dropdown-item" href="#">Something else here</a>
    </div>
</div>

    • 1
  2. Best Answer

    原因是我正在处理错误的链接（我不需要内部链接，而是外部链接）：

    $('.dropdown-menu .dropdown-toggle').on('click', function(e){
        e.preventDefault();

        $(this).closest('.dropdown-toggle').toggle();

    });
    • 0

相关问题