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Asked:2020-07-08 16:33:06 +0000 UTC2020-07-08 16:33:06 +0000 UTC

Plotly中有很多行时如何在两个图上分配相同的颜色

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如何在两张图上显示大量线条时，上下图的线条颜色是否匹配？我正在使用。

import plotly.graph_objects as go
import plotly.express as px
from plotly.subplots import make_subplots
import pandas as pd
import numpy as np
n_rows = 100
n_cols = 5
n_rows2 = 100
n_cols2 = 5


df1 = pd.DataFrame(np.random.randint(0, 100, size=(n_rows, n_cols)), columns=['col%d' % i for i in range(n_cols)])
df2 = pd.DataFrame(np.random.randint(0, 100, size=(n_rows2, n_cols2)), columns=['col%d' % i for i in range(n_cols2)])


fig_line = make_subplots(rows=2, cols=1, shared_xaxes=True, vertical_spacing=0.007, row_width=[0.23, 0.8])

# верхнии линии
for i in df1:
    fig_line.add_trace(go.Scatter(x=df1.index, y=df1[i], line=dict(width=1, dash="solid"), name = df1[i].name,  connectgaps=True), row=1, col=1) 

# нижнии линии
for n in df2:
    fig_line.add_trace(go.Scatter(x=df2.index, y=df2[n], line=dict(width=1, dash="solid" ), name = df2[n].name, connectgaps=True), row=2, col=1)

# показ в браузер
fig_line.write_html('first_figure.html', auto_open=True)
python

1 个回答

  1. Best Answer

    将命名颜色列表添加到您的代码中，该列表等于数据框中的列数，然后根据列号替换颜色。例如像这样：

    colors = ["crimson", "cyan", "darkblue", "darkcyan", "darkgoldenrod", "darkgray"]
# ^^^^ список цветов - можете выбирать любые, поддерживаемые plotly
fig_line = make_subplots(rows=2, cols=1, shared_xaxes=True, vertical_spacing=0.007, row_width=[0.23, 0.8])

# верхние линии
for i in df1:
    fig_line.add_trace(go.Scatter(x=df1.index, y=df1[i], line=dict(width=1, dash="solid",
                                color = colors[df1.columns.get_loc(i)]),
# ^^^ назначаем параметр color в соответствии с номером колонки
                                  name = df1[i].name,
                                  connectgaps=True), row=1, col=1) 

# нижние линии
for n in df2:
    fig_line.add_trace(go.Scatter(x=df2.index, y=df2[n], line=dict(width=1, dash="solid",
                                color = colors[df1.columns.get_loc(n)]),
# ^^^ назначаем параметр color в соответствии с номером колонки
                                  name = df2[n].name,
                                  connectgaps=True), row=2, col=1)

    在此处输入图像描述

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