爪哇安卓。使用 OkHttp 发送带有文本和图像的 POST 请求

您需要向服务器发送一个带有数据的 POST 请求，即 3 行和一个图像。我使用 OkHttp 库，这里是代码本身：

    static void uploadImage() {
    new Thread(new Runnable() {
        @Override
        public void run() {
    try {

        final MediaType MEDIA_TYPE_JPEG = MediaType.parse("image/jpeg");

        RequestBody req = new MultipartBody.Builder().setType(MultipartBody.FORM)
                .addFormDataPart("param1", "test1")
                .addFormDataPart("param2", "test2")
                .addFormDataPart("param3", "test3")
                .addFormDataPart("param_img", "IMG_20200903_133732.jpg",
                RequestBody.create(MEDIA_TYPE_JPEG, "storage/emulated/0/DCIM/Camera/IMG_20200903_133732.jpg"))
                .build();

        Request request = new Request.Builder()
                .url("https://mysite.ru/test.php")
                .post(req)
                .build();

        OkHttpClient client = new OkHttpClient();
        Response response = client.newCall(request).execute();

        Log.d("response", "uploadImage:" + response.body().string());

    } catch (UnknownHostException | UnsupportedEncodingException e) {
        Log.e("testtest", "Error: " + e.getLocalizedMessage());
    } catch (Exception e) {
        Log.e("testtest", "Other Error: " + e.getLocalizedMessage());
    }
        }
    }).start();
}

到目前为止，我会立即为手机上的特定图片指定一条特定路径以进行测试。结果，在服务器上，图片以这种形式出现，并没有打开，实际上不是图片：

剩下的数据（字符串）进来，被添加到数据库中，它们没有问题。这是接收的php文件，可能有问题：

<?php

include("config.php");

if(isset($_POST['param1']) && isset($_POST['param2']) && isset($_POST['param3'])){
    
        $test111 = $_POST['param1'];
        $test222 = $_POST['param2'];
        $test333 = $_POST['param3'];
    

            $uploaddir = '../img_message/';
            $uploadfile = $uploaddir . basename($_FILES['param_img']['name']);
            move_uploaded_file($_FILES['param_img']['tmp_name'], $uploadfile);

        $query = mysqli_query($connection, "INSERT INTO test_table (one, two, three) VALUES ('$test111', '$test222', '$test333')");
        
}

mysqli_close($connection);

请告诉我可能是我的错误。