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piece0f
Asked:2021-12-01 19:46:01 +0000 UTC2021-12-01 19:46:01 +0000 UTC

如何让它在 try/except 块之后只抛出一个异常？

  • 772

有这样一个“迭代器”：

class MyIterator():
    def __init__(self, lst):
        self.lst = lst
        self.counter = 0

    def __next__(self):
        try:
            z = self.lst[self.counter]
            self.counter += 2
            return z
        except:
            raise StopIteration

出现错误后，它会输出以下内容：

Traceback (most recent call last):
  File "C:/BookBot/test.py", line 10, in __next__
    z = self.lst[self.counter]
IndexError: list index out of range

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "C:/BookBot/test.py", line 22, in <module>
    print(next(x))
  File "C:/BookBot/test.py", line 14, in __next__
    raise StopIteration
StopIteration

问题：如何做到这一点，只有StopIteration，有可能做到这一点吗？

python

1 个回答

  1. Best Answer

    你在上面捕捉到这个异常并在那里输出你想要的任何东西。以及如何准确地“清除”我尚未找到Exception的当前状态：Python

    import sys
try:
    x = MyIterator(list(range(10)))
    while True:
        print(next(x))
except:
    print("Unexpected error:", sys.exc_info()[0])

    结论：

    0
2
4
6
8
Unexpected error: <class 'StopIteration'>

    默认情况下，运行时本身会输出整个异常跟踪链，除非您已经捕获到异常。

    • 1

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