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ItsIIIyTh1K
Asked:2022-02-15 23:50:55 +0000 UTC2022-02-15 23:50:55 +0000 UTC

如何检查Python字典中某个字段的值是否相同

  • 772

有一个循环（stickers_dict）通过字典。有必要以某种方式检查字典的所有元素是否对某些字段具有相同的值。如果是，则满足条件。
我附上示例：1）通过测试的字典，2）未通过测试的字典：

    {
        0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        1: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        2: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        3: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'}
    }


    {
        0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        1: {'stickerId': 2208, 'slot': '3', 'codename': 'krakow2017_signature_edward', 'name': 'Edward | Krakow 2017'},
        2: {'stickerId': 101, 'slot': '4', 'codename': 'comm01_backstab', 'name': 'Backstab'},
        3: {'stickerId': 2208, 'slot': '3', 'codename': 'krakow2017_signature_edward', 'name': 'Edward | Krakow 2017'}
    }

您可以检查任何字段，例如，stickerId，它有一个路径stickers_dict[stickers_item]['stickerId']

python

3 个回答

  1. Best Answer

    如果是按一个字段进行校验，有校验功能的感觉：

    def check_by_key(my_dict, key_check):
    values = []

    for el in my_dict.values():
        values.append(el[key_check])
        
        if len(set(values) > 1:
            return False

    return True

    对于my_dict：

    my_dict = {
        0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        1: {'stickerId': 2154, 'slot': '2', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        2: {'stickerId': 2154, 'slot': '3', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        3: {'stickerId': 2154, 'slot': '4', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'}
    }

    结果不同key_check：

    >>> check_by_key(my_dict, 'stickerId')
True
>>> check_by_key(my_dict, 'codename')
True
>>> check_by_key(my_dict, 'slot')
False
    • 2

  2. 您可以使用魔术功能str()：

    arr1 = {
    0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
    1: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
    2: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
    3: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'}
}

arr2 = {
    0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
    1: {'stickerId': 2208, 'slot': '3', 'codename': 'krakow2017_signature_edward', 'name': 'Edward | Krakow 2017'},
    2: {'stickerId': 101, 'slot': '4', 'codename': 'comm01_backstab', 'name': 'Backstab'},
    3: {'stickerId': 2208, 'slot': '3', 'codename': 'krakow2017_signature_edward', 'name': 'Edward | Krakow 2017'}
}

print(len({str(obj) for obj in arr1.values()}) == 1) # True

print(len({str(obj) for obj in arr2.values()}) == 1) # False

    对于较短的记录，您可以这样做：

    print(len({str(arr1[key]) for key in arr1}) == 1)
    • 1 
  3. from functools import reduce


x = {
        0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        1: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        2: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        3: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'}
    }


y = {
        0: {'stickerId': 2154, 'slot': '1', 'codename': 'krakow2017_signature_gla1ve', 'name': 'gla1ve | Krakow 2017'},
        1: {'stickerId': 2208, 'slot': '3', 'codename': 'krakow2017_signature_edward', 'name': 'Edward | Krakow 2017'},
        2: {'stickerId': 101, 'slot': '4', 'codename': 'comm01_backstab', 'name': 'Backstab'},
        3: {'stickerId': 2208, 'slot': '3', 'codename': 'krakow2017_signature_edward', 'name': 'Edward | Krakow 2017'}
    }

print(reduce(lambda a, b: b if x[a] == x[b] else False, x.keys()) is not False)    # True
print(reduce(lambda a, b: b if y[a] == y[b] else False, y.keys()) is not False)    # False
    • 0

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