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Федотов
Asked:2022-02-19 02:08:47 +0000 UTC2022-02-19 02:08:47 +0000 UTC

过滤一个新的 PHP 对象数组

  • 772
[
    {
      "datadoc: "2021-02-05 20:00:00",
      "summ_prih": "22420.00",
      "kod": "020045"
    },
    {
      "datadoc": "2021-02-01 16:28:21",
      "summ_prih": "4969.00",
      "kod": "040041"
    },
    {
      "datadoc": "2021-02-02 16:29:04",
      "summ_prih": "1530.00",
      "kod": "040041"
    },
    {
      "datadoc": "2021-02-01 16:30:11",
      "summ_prih": "1150.00",
      "kod": "040041"
    },
]

告诉我如何通过 datadoc 包含 2021-02-01 和 kod = 040041 的条件返回一个新的对象数组

php

1 个回答

  1. Best Answer
    <?php
$arr = [
    [
      "datadoc" => "2021-02-05 20:00:00",
      "summ_prih"=> "22420.00",
      "kod"=> "020045"
    ],
    [
      "datadoc" => "2021-02-01 16:28:21",
      "summ_prih" => "4969.00",
      "kod" => "040041"
    ],
    [
      "datadoc" => "2021-02-02 16:29:04",
      "summ_prih" => "1530.00",
      "kod" => "040041"
    ],
    [
      "datadoc" => "2021-02-01 16:30:11",
      "summ_prih" => "1150.00",
      "kod" => "040041"
    ],
];

$getfilteredData = function($arr, $datadoc, $kod) {
    return array_filter($arr, function($item) use ($datadoc, $kod) {
        return strpos($item['datadoc'], $datadoc) !== false && $item['kod'] === $kod;
    });    
};

$filteredData = $getfilteredData($arr, '2021-02-01', '040041');

//-----------------------------
print_r($filteredData);
//-----------------------------
Array
(
    [1] => Array
        (
            [datadoc] => 2021-02-01 16:28:21
            [summ_prih] => 4969.00
            [kod] => 040041
        )

    [3] => Array
        (
            [datadoc] => 2021-02-01 16:30:11
            [summ_prih] => 1150.00
            [kod] => 040041
        )

)
    • 1

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