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Guamokolatokint
Asked:2022-05-12 18:15:50 +0000 UTC2022-05-12 18:15:50 +0000 UTC

PySide 没有“看到”样式表

  • 772

我将一个单独的 qss 文件连接到 Pyside

 if __name__ == "__main__":
    app = QtWidgets.QApplication(sys.argv)
    window = App()
    File = QtCore.QFile("styles/styles.qss")
    qss = QtCore.QTextStream(File)
    app.setStyleSheet(qss.readAll())
    window.show()
    sys.exit(app.exec_())

qss内容

 QListWidget, QListView, QTreeWidget, QTreeView {
outline: 0px;
}
QListWidget {
    min-width: 120px;
    max-width: 120px;
    color: white;
    background: black;
}
QListWidget::item:selected {
    background: rgb(52, 52, 52);
    border-left: 2px solid rgb(9, 187, 7);
}
HistoryPanel::item:hover {background: rgb(52, 52, 52);}
QStackedWidget {background: rgb(30, 30, 30);}
QLabel {color: white;}

我收到一个错误

QIODevice::read (QFile, "styles/styles.qss"): device not open

文件就位，一切正常。我不明白怎么了

python

2 个回答

  1. 因为QFile您必须首先使用模式的强制性指示调用open ：

    from PyQt5.QtCore import QFile

f = QFile("styles/styles.qss")
f.open(QFile.ReadOnly)
print(f.readAll())

    从 python中使用open更容易：

    with open("styles/styles.qss") as f
    print(f.read())
    • 2
  2. Best Answer

    都想通了

    File = open("styles/style.qss",'r')
with File:
    qss = File.read()
app.setStyleSheet(qss)
    • 0

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