主页 / 问题 / 1295600
Accepted
Michael Miller
Asked:2022-06-16 01:17:08 +0000 UTC2022-06-16 01:17:08 +0000 UTC

json_encode php foreach 如何获取数据数组？

  • 772
$.ajax({
url: '/dir/file.php',
type: 'post',
dataType: 'json',

data: {action: 'ftype', btype: btype, urlForPagi: urlForPagi},

success: function(json){

if(typeof json.success !== 'undefined'){

$(document).find('.loadItemsHere').html(json.success);

} else if(typeof json.error !== 'undefined'){


return alert(json.error);

}
},
error: {...}
});


    $result[] = array();
    
    $items = $peger->getItems("SELECT * FROM `budget` WHERE `type` = '".$btype."' ORDER BY `id` DESC");
    
    foreach($items as $budget){
    
    $result[] = array(
    'id'   =>  $budget['id'],
    'type' =>  $budget['type']
    );

}

echo json_encode(['success' => $result], JSON_UNESCAPED_UNICODE);

结果，空又回来了，为什么？

var_dump()如果我这样做，我会看到一切正常：id 和 type

php

1 个回答

  1. Best Answer

    首先我们创建一个数组$results = array();

    然后在

    foreach($items as $item){

...
$json = '<div>...</div>';

array_push($results,$item);
}

echo json_encode(['success' => $results], JSON_UNESCAPED_UNICODE);
    • 0

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