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Crazy Theory
Asked:2022-07-07 00:36:07 +0000 UTC2022-07-07 00:36:07 +0000 UTC

将字符串从字符 A 修剪为字符 B

  • 772

我正在读取一个文件，其内容是这样的：

block1:
   Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nulla consequat ante nisi, id 
   vestibulum felis tempor ac. Ut semper, ligula id sollicitudin efficitur, nisl diam elementum 
   lectus, nec iaculis turpis felis non mauris. Aenean elementum tortor a tristique iaculis. Morbi 
   a aliquam diam. Donec blandit orci sit amet ante hendrerit sodales.
block2:
   <h1> Lorem ipsum dolor sit amet, consectetur adipiscing elit. Nulla consequat ante nisi, id 
   vestibulum felis tempor ac. Ut semper, ligula id sollicitudin efficitur, nisl diam elementum 
   lectus, nec iaculis turpis felis non mauris. Aenean elementum tortor a tristique iaculis. Morbi 
   a aliquam diam. Donec blandit orci sit amet ante hendrerit sodales. Morbi quis quam quis augue 
   fermentum tempus ac a ante. In vel dui interdum turpis sodales tincidunt. Praesent eget maximus 
   lorem. Phasellus mollis gravida nisi vitae pellentesque. Curabitur sed felis eget quam 
   tincidunt malesuada. </h1>

需要获取每个块的内容，我试过下面的代码：

f = open("filename.txt")
fcontent = f.read()
f.close()

contents = []
block_names = ("block1", "block2")

positions = len(block_names)
for pos in range(positions):
    current_block = block_names[pos]
    next_block = block_names[pos + 1]

    contents.append(
        fcontent[fcontent.find(current_block)] + len(current_block) + 1: next_block]
    )
python

2 个回答

  1. Best Answer

    我对其进行了一些更改，因此它通常可以工作：

    block_names = ("block1", "block2")
positions = [fcontent.find(bn) for bn in block_names]
contents = [fcontent[pos1+len(bn)+1:pos2] for bn, pos1, pos2 in zip(block_names, positions, positions[1:]+[None])]

    您一次遇到了几个错误：

    • 方括号没有闭合
    • 而不是切片的结束位置是块的名称
    • 好吧，这种排序方法不允许捕获最后一个块
    • 1

  2. 我写了一个可以解决这个问题的代码：

    word_key = '<--block-->'


def fiend_block(content=[]):
    numb = []
    for el in range(len(content)):
        if word_key in content[el]:
            numb.append(el)
    return numb


if __name__ == '__main__':
    with open('2.txt') as file:
        content_list = file.readlines()
    a = fiend_block(content_list)
    _list = []

    for numb in range(len(a)):
        sls = str()
        if not a[numb] == a[-1]:
            for el in content_list[a[numb]:a[numb+1]]:
                if not word_key in el:
                    sls += el
        else:
            for el in content_list[a[numb]:-1]:
                if not word_key in el:
                    sls += el
        _list.append(sls)

    但是现在每个块 (block1:, block2:) 必须按照您在 word_key 中指定的名称命名，并且不能在文本中使用。文件：在此处输入图像描述

    执行结果print(_list[0])：在此处输入图像描述

    • 1

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