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主页 / 问题 / 1321472
Accepted
Evendie
Evendie
Asked:2022-08-26 14:28:58 +0000 UTC2022-08-26 14:28:58 +0000 UTC 2022-08-26 14:28:58 +0000 UTC

如何通过spring处理http请求?

  • 772

我有一个任务来形成这样的查询:

POST /foo HTTP/1.1
Content-Length: 68137
Content-Type: multipart/form-data; boundary=---------------------------974767299852498929531610575

-----------------------------974767299852498929531610575
Content-Disposition: form-data; name="description"

some text
-----------------------------974767299852498929531610575
Content-Disposition: form-data; name="myFile"; filename="1.txt"
Content-Type: text/plain

(content of the uploaded file 1.txt)
-----------------------------974767299852498929531610575--

这样它由两部分组成:来自文件的文本和数据。

为了形成这样的请求,我在客户端上执行以下代码:

public void sendPOSTRequest(String url, String authData, String attachmentFilePath, String outputFilePathName) {
        
        String charset = "UTF-8";
        File binaryFile = new File(attachmentFilePath);
        String boundary = "------------------------" + Long.toHexString(System.currentTimeMillis()); // Just generate some unique random value.
        String CRLF = "\r\n"; // Line separator required by multipart/form-data.
        int responseCode = 0;

        try {
            //Set POST general headers along with the boundary string (the seperator string of each part)
            URLConnection connection = new URL(url).openConnection();
            connection.setDoOutput(true);
            connection.setRequestProperty("Content-Type", "multipart/form-data; boundary=" + boundary);
            //connection.addRequestProperty("User-Agent", "CheckpaySrv/1.0.0");
            //connection.addRequestProperty("Accept", "*/*");
            //connection.addRequestProperty("Authentication", authData);

            OutputStream output = connection.getOutputStream();
            PrintWriter writer = new PrintWriter(new OutputStreamWriter(output, charset), true);

            writer.append("--" + boundary).append(CRLF);
            writer.append("Content-Disposition: form-data;").append(CRLF);
            writer.append("Content-Type: application/json").append(CRLF);// + URLConnection.guessContentTypeFromName(binaryFile.getName())).append(CRLF);
            writer.append("{\"a\":\"asda\"}").append(CRLF);// + URLConnection.guessContentTypeFromName(binaryFile.getName())).append(CRLF);
            writer.append(CRLF);
            
            // Send binary file - part
            // Part header
            writer.append("--" + boundary).append(CRLF);
            writer.append("Content-Disposition: form-data; name=\"file\"; filename=\"" + binaryFile.getName() + "\"").append(CRLF);
            writer.append("Content-Type: application/octet-stream").append(CRLF);// + URLConnection.guessContentTypeFromName(binaryFile.getName())).append(CRLF);
            writer.append(CRLF);
            writer.flush();

            // File data
            Files.copy(binaryFile.toPath(), output);
            output.flush();

            // End of multipart/form-data.
            writer.append(CRLF).append("--" + boundary + "--").flush();

            //Отправить запрос и ожидать ответ от сервера
            responseCode = ((HttpURLConnection) connection).getResponseCode(); 
 
            if (responseCode != 200) //We operate only on HTTP code 200
            {
                return;
            }

            InputStream Instream = ((HttpURLConnection) connection).getInputStream();

            // Write PDF file 
            BufferedInputStream BISin = new BufferedInputStream(Instream);
            FileOutputStream FOSfile = new FileOutputStream(outputFilePathName);
            BufferedOutputStream out = new BufferedOutputStream(FOSfile);

            int i;
            while ((i = BISin.read()) != -1) {
                out.write(i);
            }

            // Cleanup
            out.flush();
            out.close();

        } catch (Exception e) {
            e.printStackTrace();
        }

    }

我尝试在服务器上使用以下代码处理此请求:

@RequestMapping(value = "/test6", method = RequestMethod.POST, consumes = { MediaType.MULTIPART_FORM_DATA_VALUE })
    public String test6(@RequestPart String part1) {
        System.out.println("data1: "+part1);
        System.out.println("Stop");
        return "string1";
    }

在向地址:http://localhost:8080/test6 发送 post 请求的过程中,在服务器上我收到以下消息:

WARN 2356 --- [nio-8080-exec-2] .w.s.m.s.DefaultHandlerExceptionResolver : 
Resolved [org.springframework.web.multipart.support.MissingServletRequestPartException: 
Required request part 'part1' is not present]

告诉我如何使用 multipart/form-data 类型处理这样的 post 请求?

java
  • 1 1 个回答
  • 10 Views

1 个回答

  • Voted
  1. Best Answer
    Evendie
    2022-08-26T15:35:05Z2022-08-26T15:35:05Z

    达到目的:发送一个需要修改文本+文件的请求,如下:

    在执行请求的客户端代码中:

         writer.append("--" + boundary).append(CRLF);
         writer.append("Content-Disposition: form-data; name=\"text\"").append(CRLF);
         writer.append("Content-Type: application/json").append(CRLF);
         writer.append(CRLF);
         writer.append("{\"a\":\"asda\"}").append(CRLF);
         writer.append(CRLF);
            
         // Send binary file - part
         // Part header
         writer.append("--" + boundary).append(CRLF);
         writer.append("Content-Disposition: form-data; name=\"file\"; filename=\"" + binaryFile.getName() + "\"").append(CRLF);
         writer.append("Content-Type: application/octet-stream").append(CRLF);// + URLConnection.guessContentTypeFromName(binaryFile.getName())).append(CRLF);
         writer.append(CRLF);
         writer.flush();
    

    在处理请求的服务器代码中:

    @RequestMapping(value = "/test7", method = RequestMethod.POST, consumes = {MediaType.MULTIPART_FORM_DATA_VALUE})
    public String test7(@RequestParam ("text") String text, @RequestParam("file") MultipartFile file, ModelMap modelMap) {
        System.out.println("json: "+text);
        System.out.println("fileSize: "+file.getSize()+" bytes");
        
        System.out.println("return response...");
        return "response to client";
    }
    

    想法是绑定请求name="text"的部分,其中text连接到处理此请求的控制器的部分@RequestParam ("text") String text,我们对请求的第二部分执行此操作:name="file"其中文件 与@RequestParam("file") MultipartFile 文件 ModelMap modelMap 连接。

    使用这种方法,您可以摆脱元素关联错误:Required request part ' text ' is not present或Required request part ' file ' is not present

    • 0

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