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Боков Глеб
Asked:2022-06-24 18:22:36 +0000 UTC2022-06-24 18:22:36 +0000 UTC

在 Node.js 16.x 中创建文件流时如何指定文件路径？

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这个神圣但过时的 NodeJS 截屏视频展示了这种创建文件流的方式（用 TypeScript 重写）：

import FileSystem from "fs";

const fileReadingStream: FileSystem.ReadStream = new FileSystem.ReadStream(FILE_PATH);

TypeScript 会说这种方式现在无效：

TS2345: Argument of type 'string' is not assignable to parameter of type 'ReadableOptions | undefined'

在查看了类型定义之后，我不明白现在如何建议创建文件流。

类ReadStream没有自己的（非继承的）构造函数，但stream.Readable继承自的构造函数具有以下形式

constructor(opts?: ReadableOptions);

ReadableOptions表单的接口在哪里

interface ReadableOptions extends StreamOptions<Readable> {
  encoding?: BufferEncoding | undefined;
  read?(this: Readable, size: number): void;
}

指定路径的选项在哪里？

node.js

1 个回答

  1. Best Answer

    你需要fs.cerateReadStream

    fs.createReadStream(path[, options])

    选项：

    path <string> | <Buffer> | <URL>
options <string> | <Object>

    返回

    <fs.ReadStream>

    代码示例

    import { createReadStream } from 'fs';

// Create a stream from some character device.
const stream = createReadStream('/dev/input/event0');
setTimeout(() => {
  stream.close(); // This may not close the stream.
  // Artificially marking end-of-stream, as if the underlying resource had
  // indicated end-of-file by itself, allows the stream to close.
  // This does not cancel pending read operations, and if there is such an
  // operation, the process may still not be able to exit successfully
  // until it finishes.
  stream.push(null);
  stream.read(0);
}, 100);
    • 1

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