向服务器发出请求的应用程序会抛出 NetworkOnMainThreadException，而无需在主线程中使用网络

我正在 okhttp3 库上编写一个向我的服务器发出请求的应用程序，响应正文放置在文本字段中。请求时在主线程上引发网络异常，即使所有网络代码都在并行线程中。我不明白错误的本质（我想要一个解释），但是在这个网站上解决问题的建议之一是通过 enqueue() 发出请求。是否可以在不诉诸 enqueue() 的情况下解决问题？

public class MainActivity extends AppCompatActivity {

    private OkHttpClient client;
    private Request request;
    private TextView jsonTv;
    private Button requestButton;

    private static final String ADDRESS = "http://123.123.1.23:8080/api/v1/data";


    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        jsonTv = findViewById(R.id.json_tv);
        requestButton = findViewById(R.id.request_button);


        requestButton.setOnClickListener(listener);
    }

    View.OnClickListener listener = new View.OnClickListener() {

        @Override
        public void onClick(View view) {

            AsyncRequest asyncRequest = new AsyncRequest();
            asyncRequest.execute();
        }
    };

    class AsyncRequest extends AsyncTask<Void,Void,Response>{

        @Override
        protected Response doInBackground(Void... voids) {

            client = new OkHttpClient();

            HttpUrl.Builder httpUrlBuilder = HttpUrl.parse(ADDRESS).newBuilder();

            HttpUrl httpUrl = httpUrlBuilder.build();

            request = new Request.Builder().url(httpUrl).build();

            try {
                Response response = client.newCall(request).execute();

                return response;
            }
            catch (IOException e) {

                e.printStackTrace();
                return null;
            }
        }

        @Override
        protected void onPostExecute(Response response) {
            try {
                super.onPostExecute(response);


                /*исключение на строке ниже*/
                JSONArray rootArray = new JSONArray(response.body().string());

                jsonTv.setText(String.valueOf(rootArray));

            }
            catch (IOException e) {e.printStackTrace();}
            catch (JSONException e) {e.printStackTrace();}
        }
    }
}