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hellog888
Asked:2022-07-31 01:49:01 +0000 UTC2022-07-31 01:49:01 +0000 UTC

帮助解决问题（字符串转换）Python

  • 772
from collections import Counter
def duplicate_encode(word):
    cnt = dict(Counter(word.lower()))
    str = ''
    for i in word:
        if i in cnt:
            if cnt[i] < 2:
                str += '('
            else:
                str += ')'
    return str

本练习的目标是将字符串转换为新字符串，其中如果该字符在原始字符串中仅出现一次，则新字符串中的每个字符为“(”，如果该字符在原始字符串中多次出现，则为“)”细绳。在确定字符是否重复时忽略大小写。

例子 "din" => "((("

"后退" => "()()()"

"成功" => ")())())"

"((@" => "))(("

python

2 个回答

  1. Best Answer
    def duplicate_encode(word):
    word = word.lower()
    dict = {}
    for letter in word:
        if letter not in dict:
            dict[letter] = '('
        else:
            dict[letter] = ')'
    str = ''
    for i in word:
        str += dict[i]
    return str
    • 1 
  2. from collections import Counter
def duplicate_encode(word):
    cnt = dict(Counter(word.lower()))
    str = ''
    for i in word.lower():
        if i in cnt:
            if cnt[i] == 1:
                str += '('
            else:
                str += ')'
    return str

    出于某种原因，这里for i in word.lower()：我不清楚为什么有必要添加.lower()

    • 0

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