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Myst1cal
Asked:2022-08-22 18:51:58 +0000 UTC2022-08-22 18:51:58 +0000 UTC

如何绕过错误以便脚本继续工作？

  • 772

蟒蛇脚本

import requests
from bs4 import BeautifulSoup



file = open('1.txt').read().split('\n')


url = 'https://****.ru/auth/login'
headers = {'user-agent': 'Mozilla/5.0 (X11; Linux x86_64) AppleWebKit/537.36 (KHTML, like Gecko)     Chrome/90.0.4430.212 Safari/537.36'}

session = requests.Session()
session.headers.update(headers)



url_auth = 'https://****.ru/auth/login'

for account in file:
    session = requests.Session()
    session.headers.update(headers)
    r = session.get(url)
    soup = BeautifulSoup(r.content, 'html.parser')

    csrf = soup.find('meta', {'name': 'csrf-token'})['content']

    phone = account.split(":")[0]
    password = account.split(":")[1]


    u = phone
    p = password




    payload = {
        '_csrf': csrf,
        'LoginForm[login]': phone,
        'LoginForm[password]': password,
        }

    r = session.post(url_auth, data=payload,)

该脚本有效，但在 100-300 行后出现错误

第 25 行，在 csrf = soup.find('meta', {'name': 'csrf-token'})['content'] TypeError: 'NoneType' object is not subscriptable

是否可以让脚本不注意到这个错误并在它之后继续工作？

python requests

1 个回答

  1. Best Answer

    添加尝试除外：

    import requests
from bs4 import BeautifulSoup



file = open('1.txt').read().split('\n')


url = 'https://****.ru/auth/login'
headers = {'user-agent': 'Mozilla/5.0 (X11; Linux x86_64) 
AppleWebKit/537.36 (KHTML, like Gecko)     Chrome/90.0.4430.212 
Safari/537.36'}

session = requests.Session()
session.headers.update(headers)



url_auth = 'https://****.ru/auth/login'

for account in file:
    session = requests.Session()
    session.headers.update(headers)
    r = session.get(url)
    soup = BeautifulSoup(r.content, 'html.parser')
    #####    Обработка исключения #####
    try:
        csrf = soup.find('meta', {'name': 'csrf-token'})['content']
    except:
        pass # Ошибка пропущена

    phone = account.split(":")[0]
    password = account.split(":")[1]


    u = phone
    p = password




    payload = {
        '_csrf': csrf,
        'LoginForm[login]': phone,
        'LoginForm[password]': password,
        }

    r = session.post(url_auth, data=payload,)
    • 0

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