主页 / 问题 / 1445278
Accepted
ivan
Asked:2022-09-03 15:18:35 +0800 CST2022-09-03 15:18:35 +0800 CST

为什么不进入条件？

  • 772
#pragma once

#include <utility>
#include <iostream>

template <typename T>
class Deque{

    struct Data{
        Data* next;
        Data* previous;
        T info;
    };

public:

    Deque(){
        this->right = nullptr;
        this->left = nullptr;
    }

    void push_back(T element){
        Data* ref = new Data{
            nullptr,
            right,
            std::move(element)
        };


        if(this->left == nullptr && this->right == nullptr){
            this->left == ref;
        }else{
            this->right->next = ref;
        }

        this->right = ref;
    }

    T pop_back(){
        T t = std::move(this->right->info);
        Data* ref = this->right;
        this->right = this->right->previous;
        this->right->next = nullptr;
        delete ref;
        return t;
    }

private:

    Data* left;
    Data* right;

};

为什么push_back方法中不满足条件：

if(this->left == nullptr && this->right == nullptr)

一开始，当我将第一个元素添加到容器中时，字段left和被right初始化为nullptr. 但条件仍然失败。

c++

1 个回答

  1. Best Answer

    这就是原因

    this->left == ref;

    编译器只是跳过这一行

    应该写

    this->left = ref;
    • 1

相关问题