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Accepted
alexWithoutBeard
Asked:2024-09-03 01:23:47 +0000 UTC2024-09-03 01:23:47 +0000 UTC

获取一年中的一系列周末日期

  • 772

在下面的代码中，我收到了当月的一系列周末日期。放学后，我显然根本不打印，因为我不知道如何获取今年所有的周末日期）

let weekEnd = [],
  d = new Date(),
  m = d.getMonth(),
  y = d.getFullYear(),
  totalDays = new Date(y, m, 6).getDate() && new Date(y, m, 0).getDate();

for (let i = 1; i <= totalDays; i++) {
  let dayNum = new Date(y, m, i).getDay();
  // console.log("dayNum", dayNum);
  if (dayNum === 6) weekEnd.push(i);
  else if (dayNum === 0) weekEnd.push(i);
}

console.log(weekEnd)

javascript

2 个回答

  1. const targetYear = 2024

const msDay = 24 * 60 * 60 * 1000
const msWeek = 7 * msDay
const datetime = new Date(targetYear, 0)

// Первое воскресенье
let firstSunday = datetime.getDay() === 0
  ? datetime.getTime()
  : datetime.setTime(datetime.getTime() + (msDay * (7 - datetime.getDay())))

const sundays = []
do {
  sundays.push(datetime.toDateString())
  firstSunday += msWeek // Прибавляем по неделе
  datetime.setTime(firstSunday)
} while (targetYear === datetime.getFullYear())

console.log(sundays)

    • 1
  2. Best Answer

    我不知道如何获得一年中所有的周末约会

    计算第一天休息时间 - 然后循环中的所有内容......

    console.log(test(2024))
//
function test(y) {
  const a = []
  const d = new Date(y, 0, 1)
  const t = d.getDay()
  if (t === 0) a.push(d)
  if (t < 6) d.setDate(d.getDate() + (7 - t))
  while (d.getFullYear() === y) {
    a.push(d.toISOString().split('T')[0])
    d.setDate(d.getDate() + 1)
    a.push(d.toISOString().split('T')[0])
    d.setDate(d.getDate() + 6)
  }
  return a
}

    • 1

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