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Accepted
agre
Asked:2020-11-07 23:29:32 +0000 UTC2020-11-07 23:29:32 +0000 UTC

Python无法输出负值

  • 772
number = [1,2,-5,8,-9]
max = number[0]

for num in number:
    if max < 0:
        print(max)
    max+=1
python

3 个回答

  1. Best Answer

    有可能是这样的：

    number = [1,2,-5,8,-9]

lst_number = [x for x in number if x < 0]
print(lst_number)

    如果不需要单独的列表，但只需要它的输出，你可以这样做：

    print([x for x in number if x < 0])

    如果您只需要负元素的逐个元素输出，您可以这样做：

    number = [1,2,-5,8,-9]

for num in number:
    if num < 0:
        print(num)
    • 2 
  2. filter(lambda x: x<0, number)
    • 0 
  3. number = [1,2,-5,8,-9] 
max = []

for num in number: 
   if num < 0: 
      print(num) 
      max.append(num))
    • -1

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