需要将图像保存到服务器。可以吃朴实无华的图书馆吗?当我停在 oracle 教程上时。但问题是文件保存在服务器的什么位置,如何创建路径呢?
该示例使用String path = request.getParameter("MyPath");
但我未在此处指定返回的null
内容还有另一个选项path = request.getServletContext().getRealPath("");
返回项目的父目录。是否可以在服务器上使用此选项?
@MultipartConfig
public class FileUploadServlet extends HttpServlet {
private final static Logger LOGGER =
Logger.getLogger(FileUploadServlet.class.getCanonicalName());
private static final long serialVersionUID = 7908187011456392847L;
/**
* Processes requests for both HTTP
* <code>GET</code> and
* <code>POST</code> methods.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
protected void processRequest(HttpServletRequest request,
HttpServletResponse response)
throws ServletException, IOException {
response.setContentType("text/html;charset=UTF-8");
// Create path components to save the file
final String path = request.getParameter("destination");
final Part filePart = request.getPart("file");
final String fileName = getFileName(filePart);
OutputStream out = null;
InputStream filecontent = null;
final PrintWriter writer = response.getWriter();
try {
out = new FileOutputStream(new File(path + File.separator
+ fileName));
filecontent = filePart.getInputStream();
int read;
final byte[] bytes = new byte[1024];
while ((read = filecontent.read(bytes)) != -1) {
out.write(bytes, 0, read);
}
writer.println("New file " + fileName + " created at " + path);
LOGGER.log(Level.INFO, "File {0} being uploaded to {1}",
new Object[]{fileName, path});
} catch (FileNotFoundException fne) {
writer.println("You either did not specify a file to upload or are "
+ "trying to upload a file to a protected or nonexistent "
+ "location.");
writer.println("<br/> ERROR: " + fne.getMessage());
LOGGER.log(Level.SEVERE, "Problems during file upload. Error: {0}",
new Object[]{fne.getMessage()});
} finally {
if (out != null) {
out.close();
}
if (filecontent != null) {
filecontent.close();
}
if (writer != null) {
writer.close();
}
}
}
private String getFileName(final Part part) {
final String partHeader = part.getHeader("content-disposition");
LOGGER.log(Level.INFO, "Part Header = {0}", partHeader);
for (String content : part.getHeader("content-disposition").split(";")) {
if (content.trim().startsWith("filename")) {
return content.substring(
content.indexOf('=') + 1).trim().replace("\"", "");
}
}
return null;
}
/**
* Handles the HTTP
* <code>GET</code> method.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
@Override
protected void doGet(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
/**
* Handles the HTTP
* <code>POST</code> method.
*
* @param request servlet request
* @param response servlet response
* @throws ServletException if a servlet-specific error occurs
* @throws IOException if an I/O error occurs
*/
@Override
protected void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
processRequest(request, response);
}
/**
* Returns a short description of the servlet.
*
* @return a String containing servlet description
*/
@Override
public String getServletInfo() {
return "Servlet that uploads files to a user-defined destination";
}
}
客户端不需要指定文件路径,而是必须在您的应用程序中配置文件存储路径。这可以通过不同的方式完成,例如,在 servlet 本身的初始化参数中:
在servlet中,一个参数的值可以这样获取:
调用 getParentFile() 是为了不使用文件本身的名称创建文件夹。
不需要它们,标准的 Java 语言工具就足够了:
在示例中,没有检查是否存在同名文件,没有文件夹结构构建功能(一个文件夹中的许多文件可能不方便支持),没有安全控制——这些功能超出了本示例的范围问题。