主页 / 问题 / 611846
Accepted
lounah
Asked:2020-01-07 19:02:23 +0000 UTC2020-01-07 19:02:23 +0000 UTC

PHP，解析JSON

  • 772

你好

我有看起来像这样的 JSON：

{
"response": {
"count": 10,
"items": [{...}, {...}, {...}, {...}]
}
}

items数组的每个元素包含或不包含copy_history数组。 通常，items 数组如下所示：

"items": [{
"id": 111,
"from_id": -119473366,
"owner_id": -119473366,
"date": 1483779506,
"marked_as_ads": 0,
"post_type": "post",
"text": "",
"copy_history": [{
"id": 30679,
"owner_id": -96126130,
"from_id": -96126130,
"date": 1483772560,
"post_type": "post",
"text": "",
"attachments": [{
"type": "photo",
"photo": {
"id": 456240780,
"album_id": -7,
"owner_id": -96126130,
"user_id": 100,
"photo_75": "https://pp.vk.me/...a3e/0zDlnwXV97M.jpg",
"photo_130": "https://pp.vk.me/...a3f/is7lDvyh3JE.jpg",
"photo_604": "https://pp.vk.me/...a40/Z6vXcOY-cf4.jpg",
"photo_807": "https://pp.vk.me/...a41/g9QedfvZoZg.jpg",
"width": 640,
"height": 521,
"text": "",
"date": 1483140936,
"post_id": 29964,
"access_key": ""
}
}]

有必要遍历每个 items 元素，从中获取 id 字段的值，并找出它是否包含copy_history数组。

请帮帮我。提前致谢

php

1 个回答

  1. Best Answer

    从逻辑上讲，我会这样做：

    $json = '{"response": {"count": 10, "items": [{...}, {...}, {...}, {...}] }}';
$arr = json_decode($json, true);
$res = [];
for($i = 0; $i < count($arr['response']['items']); $i++){
   $copy_history = 0;
   if(isset($arr['response']['items'][$i]['copy_history'])){
      $copy_history = 1;
   };
   array_push($res, Array(['id'] => $arr['response']['items'][$i]['id'], ['copy_history'] => $copy_history));
};
    • 1

相关问题