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Роман Тимохов
Asked:2020-01-26 17:14:09 +0000 UTC2020-01-26 17:14:09 +0000 UTC

AngularJS 发布请求中缺少数据

  • 772

有一个控制器：

betdeskApp.controller('regController', function ($scope, $http) {
    $scope.email = '';
    $scope.password = '';
    $scope.action = 'registration';
    $scope.SendRequest = function()
    {
       $http.post(CreateHref($scope.action, $scope.email, $scope.password)).success(function (data) {
            $scope.regAnswer = data;
            console.log(data);
       });
    }
});

function CreateHref(action, email, password)
{
    var str = "../model/web/index.php" + "?" + "action=" + action + "&" + "email=" + email + "&" + "password=" + password;
   // console.log(str);
    return str;
}

发送此请求时，响应为空。
服务器在 php 中并且工作正常。
也许我在发出请求时没有考虑到控制器中的某些内容？

表单提交代码：

<form class="col-sm-6" action="../model/web/index.php" method="post">
    <div class="input-group">
        <span class="input-group-addon"><i class="glyphicon glyphicon-user"></i></span>
        <input type="hidden" name="action" value="registration">
        <input id="email" type="text" class="form-control" name="email" placeholder="Email" value="" ng-model="email">
    </div><br />
    <div class="input-group">
        <span class="input-group-addon"><i class="glyphicon glyphicon-lock"></i></span>
        <input id="password" type="password" class="form-control" name="password" placeholder="Password" value="" ng-model="password">
    </div><br />
    <div class="input-group">
        <span class="input-group-addon"><i class="glyphicon glyphicon-repeat"></i></span>
        <input id="password" type="password" class="form-control" name="confirmPassword" placeholder="Confirm Password" ng-model="confPassword">
    </div><br />
    <div class="input-group">
        <button type="submit" class="btn btn-primary">Submit</button>
    </div>
</form>

这是我在日志中得到的： 在此处输入图像描述

ajax

2 个回答

  1. 应该管用：

    var config = {
    headers : {
        'Content-Type': 'application/x-www-form-urlencoded'
    }
}

var data = "action=registration&email=test@gmail.com&password=123456&confirmPassword=123456";

$http.post('../model/web/index.php', data, config)
.success(function (data, status, headers, config) {
    console.log(data);
})
.error(function (data, status, header, config) {
    console.log(data);
});
    • 1
  2. Best Answer

    Taras 走在了正确的轨道上，他的代码是：

     var config = {
    headers : {
        'Content-Type': 'application/x-www-form-urlencoded'
    }
}

var data = "action=registration&email=test@gmail.com&password=123456&confirmPassword=123456";

$http.post('../model/web/index.php', data, config)
.success(function (data, status, headers, config) {
    console.log(data);
})
.error(function (data, status, header, config) {
    console.log(data);
});

    结果证明，变量data必须为传输做好适当准备。我是这样做的：

    var data = $.param({ "action": $scope.action, "email": $scope.email, "password": $scope.password });

    在那之后一切都很好

    • 1

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