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Tick-Tack
Tick-Tack
Asked:2020-11-09 00:29:28 +0000 UTC2020-11-09 00:29:28 +0000 UTC 2020-11-09 00:29:28 +0000 UTC

如何确定用户点击了哪个按钮

  • 772

因此,屏幕上有 5 个按钮,您需要确定用户单击了哪个按钮并获取其标签,然后重定向到另一个活动。试图这样做:

protected override void OnCreate(Bundle savedInstanceState)
{
    base.OnCreate(savedInstanceState);

    SetTheme(Android.Resource.Style.ThemeDeviceDefaultLightNoActionBar);
    SetContentView(Resource.Layout.MainScreen);

    Button BtnHm = (Button)FindViewById(Resource.Id.Home);
    BtnHm.Click += SwitchActivity;

    Button BtnSrch = (Button)FindViewById(Resource.Id.Search);
    BtnSrch.Click += SwitchActivity;

    Button BtnLstOfPh = (Button)FindViewById(Resource.Id.ListOfPhotos);
    BtnLstOfPh.Click += SwitchActivity;

    Button BtnGlr = (Button)FindViewById(Resource.Id.Glory);
    BtnGlr.Click += SwitchActivity;

    Button BtnMyAcc = (Button)FindViewById(Resource.Id.MyAcc);
    BtnMyAcc.Click += SwitchActivity;
}

public void SwitchActivity(object sender, EventArgs e)
{
    Button sendBtn = (Button)sender;

    switch (sendBtn.Tag)
    {
        case 1:
            Intent toMain = new Intent(this, typeof(MainScreenActivity));
            StartActivity(toMain);
            break;
        case 2:
            Intent toSearch = new Intent(this, typeof(SearchActivity));
            StartActivity(toSearch);
            break;
        case 3:
            Intent toPhoto = new Intent(this, typeof(ListOfPhotoActivity));
            StartActivity(toPhoto);
            break;
        case 4:
            Intent toGlory = new Intent(this, typeof(GloryActivity));
            StartActivity(toGlory);
            break;
        case 5:
            Intent toUser = new Intent(this, typeof(UserActivity));
            StartActivity(toUser);
            break;
    }
}

但它在case数字上强调了我,并写道需要一个常数值。怎么修?

在此处输入图像描述

android
  • 4 4 个回答
  • 10 Views

4 个回答

  • Voted
  1. Роман Нечаев
    2020-11-09T01:45:21Z2020-11-09T01:45:21Z

    您需要为每个按钮分配一个 Id,并在 switch() 构造中,按 id 查找视图元素。例如:

         switch(sendBtn.getId()){
    case R.id.btn1:
    ...
    case R.id.btn2:
    ...}
    

    如果这不适合你的编程语言,我希望我的回答能给你一个关于如何解决这个问题的提示。祝你好运)

    • 3
  2. Best Answer
    John
    2020-11-09T02:03:50Z2020-11-09T02:03:50Z

    无论您在 xml 中写入什么,任何值都将被打包到 Tag 属性中(Tag 仍然是一个对象)。当你请求一个属性时,你总会收到一个对象,所以你需要解包:

    switch ((int) sendBtn.Tag)
    
    • 1
  3. LordValDeMar
    2020-02-08T15:59:14Z2020-02-08T15:59:14Z

    XAML

    `<Button x:Name="But_01" BindingContext="01" Clicked="Button_Click />" 
     <Button x:Name="But_02" BindingContext="02" Clicked="Button_Click />"`
    

    XAML.CS

    `private void Button_Click (object sender, EventArgs e)
    {
        Button btn = (Button)sender;
        String name_button = Convert.ToString(btn.BindingContext);
        switch (name_button)
        {
            case "01":
                //Нажата кнопка 01
                break;
            case "02":
                //Нажата кнопка 02
                break;
        }
    }`
    
    • 1
  4. Mikhail Efremov
    2020-11-09T04:38:19Z2020-11-09T04:38:19Z

    为什么会出现所有这些情况?您还可以为每个按钮创建单独的事件。像这样:

    protected override void OnCreate(Bundle savedInstanceState)
    {
      base.OnCreate(savedInstanceState);
    
      SetTheme(Android.Resource.Style.ThemeDeviceDefaultLightNoActionBar);
      SetContentView(Resource.Layout.MainScreen);
    
      Button BtnHm = (Button)FindViewById(Resource.Id.Home);
      BtnHm.Click += SwitchActivityByHm;
    
      Button BtnSrch = (Button)FindViewById(Resource.Id.Search);
      BtnSrch.Click += SwitchActivityBySrch;
    
      Button BtnLstOfPh = (Button)FindViewById(Resource.Id.ListOfPhotos);
      BtnLstOfPh.Click += SwitchActivityByLstOfPh;
    
      Button BtnGlr = (Button)FindViewById(Resource.Id.Glory);
      BtnGlr.Click += SwitchActivityByGlr;
    
      Button BtnMyAcc = (Button)FindViewById(Resource.Id.MyAcc);
      BtnMyAcc.Click += SwitchActivityByMyAcc;
    }
    
    public void SwitchActivityByHm(object sender, EventArgs e)
    {
      Intent toMain = new Intent(this, typeof(MainScreenActivity));
      StartActivity(toMain);
    }
    
    public void SwitchActivityBySrch(object sender, EventArgs e)
    {
      Intent toSearch = new Intent(this, typeof(SearchActivity));
      StartActivity(toSearch);
    }
    
    public void SwitchActivityByLstOfPh(object sender, EventArgs e)
    {
      Intent toPhoto = new Intent(this, typeof(ListOfPhotoActivity));
      StartActivity(toPhoto);
    }
    
    public void SwitchActivityByGlr(object sender, EventArgs e)
    {
      Intent toGlory = new Intent(this, typeof(GloryActivity));
      StartActivity(toGlory);
    }
    
    public void SwitchActivityByMyAcc(object sender, EventArgs e)
    {
      Intent toUser = new Intent(this, typeof(UserActivity));
      StartActivity(toUser);
    }
    
    • 0

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