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Asked:2020-04-23 03:01:48 +0000 UTC2020-04-23 03:01:48 +0000 UTC

在 JavaScript 中反序列化 JSON 对象

  • 772

需要获取 Man 类的对象列表

public class Man
{
    public int Id { get; set; }
    public string Firstname { get; set; }
    public string Secondname { get; set; }
    public int Age { get; set; }
}

向服务器发送请求

$.ajax({
    url: url,
    type: "POST",
    data: {
        "count": count
    },
    dataType: "json"
})

在控制器方法中，我形成一个对象数组并将其发送给客户端

for (int i = 0; i < dif; i++)
{
    mans[i] = await manContext.Mans.FirstOrDefaultAsync(m => m.Id == mansCount - dif + i);
}
return Json(mans);

如何使用 JS 从 JSON 中获取 Man 对象的字段值（姓名、年龄等）？

javascript

1 个回答

  1. Best Answer

    请求示例：

    $.ajax({
type: "POST", 
url: url,
data: { count: 'count' },
dataType:'json',
success: function(data){
alert ( data.Firstname),
alert ( data.Age)
}
});

    AJAX POST 处理表单按钮事件

    <!DOCTYPE html>
<html>
<head>
    <title>jQuery AJAX POST</title>
    <meta charset="utf-8">
</head>
<body>

<div id="response">
    <pre></pre>
</div>

<form id="my-form">
    <button type="submit">Submit</button>
</form>

<script src="//ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<script>
    (function($){
        function processForm( e ){
            $.ajax({
                url: 'http://ip-api.com/json/',
                dataType: 'text',
                type: 'post',
                contentType: 'application/x-www-form-urlencoded',
                data: $(this).serialize(),
                success: function( data, textStatus, jQxhr ){
                    $('#response pre').html( data );
                },
                error: function( jqXhr, textStatus, errorThrown ){
                    console.log( errorThrown );
                }
            });

            e.preventDefault();
        }

        $('#my-form').submit( processForm );
    })(jQuery);
</script>
</body>
</html>

    C# JSON 序列化

    [DataContract]
class Man
{
     [DataMember]
     public int Id { get; set; }
     [DataMember]
     public string Firstname { get; set; }
     [DataMember]
     public string Secondname { get; set; }
     [DataMember]
     public int Age { get; set; }
     public Man() { }
     public Man(int Id, string Firstname, int Age)
     {
         this.Id = Id;
         this.Firstname = Firstname;
         this.Age = Age;
     }
}

    Json 反序列化 C#

    DataContractJsonSerializer jsonFormatter = new DataContractJsonSerializer(typeof(Man));

Man newitems = (Man)jsonFormatter.ReadObject(File.OpenRead("Man.json"));

    json javascript

    <script>
	var user = '{ "Id": 1, "Firstname": "Вася", "Secondname": "Васильев", "Age": 28 }';
	user = JSON.parse(user);
	alert( user.Age );
</script>

    • 2

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