如何在 c++ Visual Studio 的控制台中返回光标坐标的当前值?最好举个例子
主页
/
user-305753
Steg_Brind's questions
我有 4 个功能case1();
case2()
;case3()
; case4();
还有5个功能start();
通过按下按钮启动,功能本身start()
应该运行case1();
case2()
;case3();
case4();
结果,原来case1启动了,其余的都没有启动。
var flag = 1;
//var w_f = document.getElementById("width_of_field").value;
//var h_f = document.getElementById("height_of_field").value;
var w_f = 3;
var h_f = 3;
var acr1 = w_f * h_f;
function gameover(fr, sec, thr) {
$("#go").css('display', 'block');
$("#" + fr).css('background-color', 'red');
$("#" + sec).css('background-color', 'red');
$("#" + thr).css('background-color', 'red')
}
function case1() {
var attemps_of_one_string = Math.floor(w_f / 3 * 2);
//var attemps = 0;
for (var d = 0; d < acr1; d++) {
/*if (attemps === attemps_of_one_string) {
d = d + 2;
attemps = 0;
}
attemps++;*/
var first = document.getElementById(String(d + 1)).innerHTML;
var second = document.getElementById(String(d + 2)).innerHTML;
var third = document.getElementById(String(d + 3)).innerHTML;
if (first == second && first == third && first != " ") {
if (first == "X") {
document.getElementById("live").innerHTML = "КРЕСТИКS WIN";
gameover(d + 1, d + 2, d + 3)
} else {
document.getElementById("live").innerHTML = "НОЛИКS WIN";
gameover(d + 1, d + 2, d + 3)
}
}
}
}
function case2() {
for (var k = 0; k < acr1; k++) {
var first = document.getElementById(String(k + 1)).innerHTML;
var second = document.getElementById(String(k + w_f + 1)).innerHTML;
var third = document.getElementById(String(k + (w_f * 2) + 1)).innerHTML;
if (first == second && first == third && first != " ") {
if (first == "X") {
document.getElementById("live").innerHTML = "КРЕСТИКS WIN";
gameover(k + 1, k + w_f + 1, k + (w_f * 2) + 1)
} else {
document.getElementById("live").innerHTML = "НОЛИКS WIN";
gameover(k + 1, k + w_f + 1, k + (w_f * 2) + 1)
}
}
}
}
function x_o(num) {
if (flag === 1) {
flag = 0;
document.getElementById(num).innerHTML = "X";
document.getElementById("live").innerHTML = "<b>НОЛИК</b>";
$("#" + num).attr('disabled', "disabled");
case1();
case2()
} else {
flag = 1;
document.getElementById(num).innerHTML = "O";
document.getElementById("live").innerHTML = "<b>КРЕСТИК</b>";
$("#" + num).attr('disabled', "disabled");
case1();
case2()
}
}
html,
body {
margin: 0;
padding: 0;
background: #878787
}
.container {
max-width: 423px;
width: 100%;
margin: 0 auto;
display: flex;
flex-wrap: wrap;
text-align: center
}
.sqr {
text-align: center;
line-height: 200%;
background-color: transparent;
border: black solid 0.5px;
width: 33.33333333333333%;
font-family: "arial";
font-size: 10vh
}
.sqr:disabled {
color: black
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>КРЕСТИК И НОЛИК</title>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/2.0.3/jquery.min.js"></script>
<body>
<div class="container">
<button class="sqr" id="1" onclick="x_o(1)"> </button>
<button class="sqr" id="2" onclick="x_o(2)"> </button>
<button class="sqr" id="3" onclick="x_o(3)"> </button>
<button class="sqr" id="4" onclick="x_o(4)"> </button>
<button class="sqr" id="5" onclick="x_o(5)"> </button>
<button class="sqr" id="6" onclick="x_o(6)"> </button>
<button class="sqr" id="7" onclick="x_o(7)"> </button>
<button class="sqr" id="8" onclick="x_o(8)"> </button>
<button class="sqr" id="9" onclick="x_o(9)"> </button>
<p id="live" style="display: block; margin-left: 43%"><b>КРЕСТИК</b></p>
<p id="go" style="cursor: pointer; display: none; margin-top: 10%; font-family: 'arial'" onclick="$(this).hide(50), $('button').text(' ').css('background-color', 'transparent').attr('disabled', false), $('#live').text('КРЕСТИК'), flag=1"><b>ПОПРОБОВАТЬ СНОВА</b></p>
</div>
</body </html>
我正在尝试创建一个三分球游戏。我第一次想做 3 对 3 场。然后让用户可以选择字段的宽度和高度。但现在不是这样。case1 函数(它计算水平边距并尝试选择获胜者)正常工作。case2 函数应该做同样的事情,只是垂直计算字段。所以case2根本行不通。不知道为什么
我有一个函数,这个函数在按下按钮的时候执行,然后在函数中触发一个循环,循环中有一个setTimeout带有闭包函数。问题是,如何通过按下另一个按钮,使具有循环的功能完全停止/中断?