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主页 / 问题 / 834046
Accepted
Alexander Semikashev
Alexander Semikashev
Asked:2020-05-27 17:40:12 +0000 UTC2020-05-27 17:40:12 +0000 UTC 2020-05-27 17:40:12 +0000 UTC

合并两个 SQL 查询

  • 772

有两张桌子。第一个包含公司的表company,字段:company_id, company_name。

第二个表带有acts act,字段:act_id,receipt_date(收据日期),issue_date(签发日期,可能为Null)。

因此,我需要一个查询,以便数据采用这种形式:

company_id…… company_name_ количество полученых актов за 27.02.2018_количество выданных актов за 27.02.2018

company_id…… company_name_ количество полученых актов за 26.02.2018_количество выданных актов за 26.02.2018

等等...

请求是从我单独获得的,这没有问题。

select c.id company_id, c.name company, DATE(receipt_date) receipt, count(*) count from act
join company c on c.id = act.company_id
where 

    act.is_delete = 0
group by act.company_id, receipt

 

select c.id company_id, c.name company, DATE(issue_date) issue, count(*) count from act
    join company c on c.id = act.company_id
    where 

        act.is_delete = 0
    group by act.company_id, issue

但是如何组合这些请求呢?这没用。

sql
  • 1 1 个回答
  • 10 Views

1 个回答

  • Voted
  1. Best Answer
    Tony DM
    2020-05-28T07:16:17Z2020-05-28T07:16:17Z

    选项1

    select company_id,
           date(receipt_date) as "dt",
           count(*)           as "qty"
      into #receipt_total
      from act
    where is_delete = 0
    group by company_id,
            "dt"
    ;
    -- indexes
    
    select company_id,
           date(receipt_date) as "dt",
           count(*)           as "qty"
      into #issue_total
      from act
    where is_delete = 0
    group by company_id,
            "dt"
    ;
    -- indexes
    
    
    select isnull(t1.company_id, t2.company_id) as "company_id",
           isnull(t1.dt, t2.dt)                 as "dt",
           isnull(t1.qty, 0)                    as "qty_receipt",
           isnull(t2.qty, 0)                    as "qty_issue"
      into #result
      from #receipt_total    as t1
      full join #issue_total as t2 on t2.company_id = t1.company_id
                                  and t2.dt = t1.dt
    ;
    
    select t1.company_id,
           t2.company_name,
           t1.dt,
           t1.qty_receipt,
           t1.qty_issue
      from #result as t1
      join company as t2 on t2.id = t1.company_id
    ;
    

    选项 2

    select company_id,
           'receipt'          as "rtype",
           date(receipt_date) as "dt",
           count(*)           as "qty"
      into #receipt_total
      from act
    where is_delete = 0
    group by company_id,
            "dt"
    ;
    -- indexes
    
    select company_id,
           'issue'            as "rtype",
           date(receipt_date) as "dt",
           count(*)           as "qty"
      into #issue_total
      from act
    where is_delete = 0
    group by company_id,
            "dt"
    ;
    -- indexes
    
    select *
      into #total_data
      from #receipt_total
    union all
    select *
      from #issue_total
    ;
    
    select company_id,
           dt,
           sum(case when rtype = 'receipt'
                     then qty
                 end)                        as "qty_receipt",
           sum(case when rtype = 'issue'
                     then qty
                 end)                        as "qty_issue"
      into #result
      from #total_data
    ;
    
    select t1.company_id,
           t2.company_name,
           t1.dt,
           t1.qty_receipt,
           t1.qty_issue
      from #result as t1
      join company as t2 on t2.id = t1.company_id
    ;
    
    • 0

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