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Accepted
Vitaly M.
Asked:2020-09-25 18:47:59 +0800 CST2020-09-25 18:47:59 +0800 CST

Pojo 对象字段名称

  • 772

为什么objectMapper它看不到对象的字段设置器Pojo？

班级User

    public class User {
        private String ID;
        private boolean ACTIVE;
        private String UF_PHONE_INNER;

        public String getID() {
            return ID;
        }

        public void setID(String ID) {
            this.ID = ID;
        }
... и т.д.

班级Users

public class Users {
    private User[] result;

    public User[] getUsers() {
        return result;
    }

    public void setResult(User[] result) {
        this.result = result;
    }
и т.д....

拆解JSON

log.debug("jsonString is {}",jsonString);
users.setResult(objectMapper.readValue(jsonString, Users.class).getUsers());

我得到：

DEBUG log:71 - jsonString is {"result":[{"ID":"1","ACTIVE":true,...
WARN  log:81 - com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "ID" (class ru.bityard.bitrix24.User), not marked as ignorable (3 known properties: "id", "active", "uf_PHONE_INNER"])

我不明白为什么他看到id而不是ID？？？我的印象是解析器将字段ID视为对象......

java

1 个回答

  1. Best Answer

    杰克逊看到方法setID认为该字段将被调用iD。@JsonProperty以 java 风格添加注解和名称字段

    public class User {
    private String id;

    @JsonProperty("ID")
    public void setId(String id) {
        this.id= id;
    }
}
    • 3

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