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主页 / 问题 / 912060
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Вячеслав Чернышов
Вячеслав Чернышов
Asked:2020-11-27 15:33:00 +0000 UTC2020-11-27 15:33:00 +0000 UTC 2020-11-27 15:33:00 +0000 UTC

SQL 语法错误:WITH 语句

  • 772

我对 mariaDB 有一个查询:

SELECT AVG(selectOnStop.time_avg)                                             AS global_avg_time,
       AVG(selectFromStopTaskProcessor.time_avg)                              AS qmr_task_time,
       AVG(selectOnStop.time_avg) - AVG(selectFromStopTaskProcessor.time_avg) AS postprocessing
FROM (SELECT
        global_task_id,
        SUM(time_from_start),
        SUM(time_from_start) / 1000000 AS time_avg
      FROM task AS t
             INNER JOIN recorderevent AS r ON (CONCAT(r.task_id, '0', SUBSTRING(r.`shard_alias` FROM 7)) = t.id)
      WHERE r.event_name = 'STOP'
      GROUP BY global_task_id
      ORDER BY SUM(time_from_start) DESC) AS selectOnStop
       JOIN (SELECT global_task_id, SUM(time_from_start) / 1000000 AS time_avg
             FROM task AS t
                    INNER JOIN recorderevent AS r ON (CONCAT(r.task_id, '0', SUBSTRING(r.`shard_alias` FROM 7)) = t.id)
             WHERE r.event_name = 'QMR_STOP_TASK_PROCESSOR'
             GROUP BY global_task_id
             ORDER BY SUM(time_from_start) DESC) AS selectFromStopTaskProcessor;

该请求正在运行。我决定使用 WITH 语句重写它。

WITH selectOnStop (time_start, time_avg) AS (SELECT
                                               SUM(time_from_start)           AS time_start,
                                               SUM(time_from_start) / 1000000 AS time_avg
                                             FROM task AS t
                                                    INNER JOIN recorderevent AS r
                                                               ON (CONCAT(r.task_id, '0', SUBSTRING(r.`shard_alias` FROM 7)) = t.id)
                                             WHERE r.event_name = 'STOP'
                                             GROUP BY global_task_id
                                             ORDER BY SUM(time_from_start) DESC)
    ,
     selectFromStopTaskProcessor (time_average) AS (SELECT SUM(time_from_start) / 1000000 AS time_average
                                                    FROM task AS t
                                                           INNER JOIN recorderevent AS r
                                                                      ON (CONCAT(r.task_id, '0', SUBSTRING(r.`shard_alias` FROM 7)) = t.id)
                                                    WHERE r.event_name = 'QMR_STOP_TASK_PROCESSOR'
                                                    GROUP BY global_task_id
                                                    ORDER BY SUM(time_from_start) DESC)

SELECT AVG(selectOnStop.time_avg)                                                 AS global_avg_time,
       AVG(selectFromStopTaskProcessor.time_average)                              AS qmr_task_time,
       AVG(selectOnStop.time_avg) - AVG(selectFromStopTaskProcessor.time_average) AS postprocessing
FROM selectOnStop
       JOIN selectFromStopTaskProcessor;

事实上,我只是将选择移到单独的查询中。写入以下内容:

[42000][1064] (conn=3) 检查与您的 MariaDB 服务器版本相对应的手册,以了解在 'selectOnStop (time_start, time_avg) AS (SELECT [42000][1064]在第 1 行的 'selectOnStop (time_start, time_avg) AS (SELECT ' 附近使用正确语法的服务器版本查询是: WITH selectOnStop (time_start, time_avg) AS (SELECT SUM(time_from_start) AS time_sta ...

告诉我我做错了什么,以及需要在请求中更正哪些内容才能使其正常工作?

sql
  • 1 1 个回答
  • 10 Views

1 个回答

  • Voted
  1. Best Answer
    Мелкий
    2020-11-27T17:50:45Z2020-11-27T17:50:45Z

    当收到看似正确的请求的语法错误时,遵循错误文本中的建议是有意义的:

    检查与您的 MariaDB 服务器版本相对应的手册

    并检查有关您的 DBMS 版本的此语法的文档。

    对于mariadb表达式支持,不久前WITH出现在 alpha 版本10.2.1中。第一个稳定版本是 10.2.6。您有版本 10.1.37 - 即以前的分支,因此尚不支持它。common table expressionCTE

    • 1

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